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Q.11: Consider the balanced Y-Y three-phase system in Fig. Q11. (a) Obtain the line currents Ia, I and Ic, the line voltages Vab, Voc and Vca, the load voltages VAN, VBN and VCN; (b) Describe the relationships between the phase voltages and the line voltages. 440/0° V 440/120° V J a la 6-j8Q2 440-120° V 1₂ Figure Q11 A 6-j8 12 N 6-j8Q

Q.11: Consider the balanced Y-Y three-phase system in Fig. Q11. (a) Obtain the line currents Ia, I and Ic, the line voltages Vab, Voc and Vca, the load voltages VAN, VBN and VCN; (b) Describe the relationships between the phase voltages and the line voltages. 440/0° V 440/120° V J a la 6-j8Q2 440-120° V 1₂ Figure Q11 A 6-j8 12 N 6-j8Q

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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### Question 11: **Consider the balanced Y-Y three-phase system in Fig. Q11.** (a) Obtain the line currents \( I_a, I_b, \) and \( I_c \), the line voltages \( V_{ab}, V_{bc} \) and \( V_{ca} \), the load voltages \( V_{AN}, V_{BN} \) and \( V_{CN} \). (b) Describe the relationships between the phase voltages and the line voltages. **Figure Q11:** The figure depicts a balanced Y-Y three-phase system with the following characteristics: 1. **Sources:** - **Phase a:** Voltage source of \( 440 \angle 0^\circ \text{V} \). - **Phase b:** Voltage source of \( 440 \angle 120^\circ \text{V} \). - **Phase c:** Voltage source of \( 440 \angle -120^\circ \text{V} \). 2. **Line Configuration:** - The three lines (a, b, and c) are connected to the balanced load. - The neutral point (n) is connected to the neutral point (N) of the load. 3. **Load:** - Each phase of the load is connected in a Y-configuration. - Each load impedance is given as \( 6 - j8 \Omega \). ### Detailed Explanation of the Diagram: 1. **Source Voltages:** - The source at point 'a' has a voltage of \( 440 \angle 0^\circ \) V. - The source at point 'b' has a voltage of \( 440 \angle 120^\circ \) V. - The source at point 'c' has a voltage of \( 440 \angle -120^\circ \) V. 2. **Load Configuration:** - Point 'A' is connected to the neutral point 'N' through an impedance of \( 6 - j8 \Omega \). - Point 'B' is connected to the neutral point 'N' through an impedance of \( 6 - j8 \Omega \). - Point 'C' is connected to the neutral point 'N' through an impedance of \( 6 - j8 \Omega \). 3. **Currents:** - Current \( I_a \) flows through the impedance from
Transcribed Image Text:### Question 11: **Consider the balanced Y-Y three-phase system in Fig. Q11.** (a) Obtain the line currents \( I_a, I_b, \) and \( I_c \), the line voltages \( V_{ab}, V_{bc} \) and \( V_{ca} \), the load voltages \( V_{AN}, V_{BN} \) and \( V_{CN} \). (b) Describe the relationships between the phase voltages and the line voltages. **Figure Q11:** The figure depicts a balanced Y-Y three-phase system with the following characteristics: 1. **Sources:** - **Phase a:** Voltage source of \( 440 \angle 0^\circ \text{V} \). - **Phase b:** Voltage source of \( 440 \angle 120^\circ \text{V} \). - **Phase c:** Voltage source of \( 440 \angle -120^\circ \text{V} \). 2. **Line Configuration:** - The three lines (a, b, and c) are connected to the balanced load. - The neutral point (n) is connected to the neutral point (N) of the load. 3. **Load:** - Each phase of the load is connected in a Y-configuration. - Each load impedance is given as \( 6 - j8 \Omega \). ### Detailed Explanation of the Diagram: 1. **Source Voltages:** - The source at point 'a' has a voltage of \( 440 \angle 0^\circ \) V. - The source at point 'b' has a voltage of \( 440 \angle 120^\circ \) V. - The source at point 'c' has a voltage of \( 440 \angle -120^\circ \) V. 2. **Load Configuration:** - Point 'A' is connected to the neutral point 'N' through an impedance of \( 6 - j8 \Omega \). - Point 'B' is connected to the neutral point 'N' through an impedance of \( 6 - j8 \Omega \). - Point 'C' is connected to the neutral point 'N' through an impedance of \( 6 - j8 \Omega \). 3. **Currents:** - Current \( I_a \) flows through the impedance from
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