Q3: explain the result of the following: Matlab 1) n=input('enter an integer : '); if n>0 disp('the number is positive') elseif n<0 disp('the number is negative') else disp('the number is zero') end 2) x=input('enter the x value : '); if x<10 && x>5 disp('undefined y value') elseif x>==10 y=5/x^2; fprintf('the else fprintf('the end y value =%0.2 f/n ¹,y); y value = %d/n',5);
Q3: explain the result of the following: Matlab 1) n=input('enter an integer : '); if n>0 disp('the number is positive') elseif n<0 disp('the number is negative') else disp('the number is zero') end 2) x=input('enter the x value : '); if x<10 && x>5 disp('undefined y value') elseif x>==10 y=5/x^2; fprintf('the else fprintf('the end y value =%0.2 f/n ¹,y); y value = %d/n',5);
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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i need the answer quickly
![Q3: explain the result of the following: Matlab
1)
n=input('enter an integer : ');
if n>0
disp('the number is positive')
elseif n<0
disp('the number is negative')
else
disp('the number is zero')
end
2)
x=input('enter the x value : ');
if x<10 && x>5
disp('undefined y value')
elseif x>==10
y=5/x^2;
fprintf('the y value =%0.2 f/n ¹,y);
else
fprintf('the y value = %d/n',5);
end](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02d09fe5-175a-4f56-9495-20755c776e01%2Fe59e4213-dc21-48a2-b0ed-8975c040f0f3%2Fuq00fje_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q3: explain the result of the following: Matlab
1)
n=input('enter an integer : ');
if n>0
disp('the number is positive')
elseif n<0
disp('the number is negative')
else
disp('the number is zero')
end
2)
x=input('enter the x value : ');
if x<10 && x>5
disp('undefined y value')
elseif x>==10
y=5/x^2;
fprintf('the y value =%0.2 f/n ¹,y);
else
fprintf('the y value = %d/n',5);
end
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