Q3: A tensile test on a cold worked brass gave the following results. The diameter of the test specimen d= 16 mm and the gauge lenth was 80 mm After fracture the gauge length was 85 mm and the fracture point was was 15 mm diameter. The maxiumu load was 150 KN. The load and extension at the elastic limit were 70 KN and 0.5 mm, respectively. Calculate the modulus o elasticity. Calculate the % of elongation and % of reduced cross sectiona area

Q3: A tensile test on a cold worked brass gave the following results. The diameter of the test specimen d= 16 mm and the gauge lenth was 80 mm After fracture the gauge length was 85 mm and the fracture point was was 15 mm diameter. The maxiumu load was 150 KN. The load and extension at the elastic limit were 70 KN and 0.5 mm, respectively. Calculate the modulus o elasticity. Calculate the % of elongation and % of reduced cross sectiona area

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

None
The brass has a shear modulus (G) of 40 GPa. In the torsion test calculated results, (G) was found to be 37 830 MPa. What is the percentage of errors in the experiment? Select one: a. 0.54% O b. 5.425% c. 0.05425% O d. 3.779%
The yield stress for mild steel is 207MP.. A specimen with diameter of 0.01lm and length of 0.1m is subjected to a load of weight of 10kg, and the resulting elongation is 6.077 microns. Determine whether the stress is above or below the yield stress, and if it is below, compute the Young's modulus of the material.
3. A rod-shaped MgO specimen with round cross section is tested with the three-point bend method. What is the calculated minimum radius without fracture if the applied load is 5560 N, the flexural strength is 105 MPa, and the separation between the two support pins is 45 mm?
A bar made of carbon-steel of size 12mm x 20mm has a yield stress of 400 MPa and ultimate tensile strength of550 MPa. Tha gauge length of the specimen tested under tension loading is 350mm. a. Determine its elongation when a tension load of 75 KN is applied. b. Determine the maximum load the bar can take before it fractures. Take Youngs Modulus of steel as 200,000 MPa
A steel rod specimen with a diameter of 200mm was subjected to a force 5000 N in the stress-strain experiment, if the area of the rod at fracture was 25434 mm^2, determine the percentage of the sample ductility (RA).
A tensile test specimen of 1045 hot-rolled steel having a diameter of 0.505 in. and a gage length of 2.00 in. was tested to fracture. Stress and strain data obtained during the test are shown. Determine the ultimate strength. Stress (ksi) 60 50- 40- 30- 20 10- 0 0 0 Upper scale O 66 ksi 28 ksi O 72 ksi O 53 ksi O 62 ksi Lower scale. 0.025 0.050 0.075 0.100 0.125 0.150 0.175 0.002 0.004 0.006 0.008 0.010 0.012 0.014 Strain (in./in.)
The table below shows the deformation data that resulted from applying a pure tensile load to a brass alloy rod with an initial length of 30 mm and a diameter of 10 mm. This rod was subjected to necking and beyond necking deformation. The data at fracture is shown in the last row. Applied Load (N) Length (mm) Diameter (mm) 75,100 33.8 68, 250 34.9 50,200 35.7 6.7 Solve for the TRUE STRESS/ES and TRUE STRAINS. 8.3 7.8
Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025