Q3/ A: For the power system shown, calculate fault current and when a 3-phase fault occurs at point F. The data are given below. Equipment XI X2 X. Rating G 20% 20% 6% 2.50 50 MVA-11 KV TI 10% 10% 10% 11/132 KV,30 MVA LINE 1000 1000 3000 T2 10% 10% 10% 132/11 KV,30 MVA MI 25% 25% 6% 40 MVA,1IKV M2 25% 25% 6% 40 MVA,11KV Line MI TI T2 M1 Fault

Q3/ A: For the power system shown, calculate fault current and when a 3-phase fault occurs at point F. The data are given below. Equipment XI X2 X. Rating G 20% 20% 6% 2.50 50 MVA-11 KV TI 10% 10% 10% 11/132 KV,30 MVA LINE 1000 1000 3000 T2 10% 10% 10% 132/11 KV,30 MVA MI 25% 25% 6% 40 MVA,1IKV M2 25% 25% 6% 40 MVA,11KV Line MI TI T2 M1 Fault

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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2) The power system consists of generators, motors, transformers, and transmission lines. The ratings are as follows: G1: 3-phase generator 25 MVA, 11 KV, X = 20% M1: 3-phase motor M2: 3-phase motor T1:3 single phase transformers T2: 3-phase transformer Line: 15 MVA, 13 KV, X = 25% 7.5 MVA, 13 KV, X = 25% Single phase transformer rating 30 MVA, 6.9/69 KV X = 10% Three phase transformer rating 30 MVA, 13.8/69 KV X = 10% Χ - 50 Ω = Τι G₁ 2. Line Figure 1. 3 T2 Σ M₁ Δι M2 Find the reactance (X) in p.u. units, given the base value of 25 MVA, 11 KV.
Magnitude of Severity of fault is expressed in terms of Magnitude of Recovery Types of fault All of these the fault current voltage
c) Figure 4 (c) shows two (2) 11 kV/415V distribution transformers are connected using 2 incomings with sectionalizing breakers at HV and LV side. briefly summarize the switching procedure for maintenance personnel to shutdown the Transformer 2 for breaker servicing work at LV side and put back in-service. Supply line 1 Supply line 2 Disconnect switch Disconnect switch HV side breaker HV side breaker HV sectionilizing breaker HV busleection 1 HV bus section 2 Transformer 1 Transtormer 2 Indoor switchgear LV side breaker LV sectionilizing breaker LV bus section 1 LV bus section 2 Feeders breakers Outcoming feeders Figure 4 (c)
B1
Different type of fault in power system
a) In Three Phase Faults that will occur separately on A, B, C and D Busbars, Calculate the currents. b) Maximum fault currents to pass through KA, KB, KC1, KC and KD Protection devices determine. Help me please... Thank you so much.
1. A Zone 2 fault is detected in 25 cycles of a 60 Hz power system and the circuit breaker clears in 5 cycles. Calculate the fault clearing time for this case. a) 60 ms b) 500 ms c) 120 ms d) 150 ms 2. The Burden on a CT should always be kept a) High b) Low c) Either, because burden does not affect the CT d) At the rated burden value for the CT 3. The purpose of backup protection is a) To increase speed b) To leave no blind spots c) To guard against failure of primary d) To increase reach 4. In distance protection scheme, which Zone is set to trip instantaneous without any delay? a) Zone 3 b) Zone 2 c) Zone 1 d) All of the above 5. The protective relay is provided to: 1) Provide additional safety by limiting arcing current during circuit breaker operation. 2) Close the contacts when the actuating quantity attains a certain predetermined value. a) Only 1 b) Only 2 c) Both 1 and 2 d) None of these
Which of the following characterizes series faults? All of these Imbalance in series impedance No connection between lines No connection between lines and neutral
A 15 MVA, 6.6 kV, wye connected generator has X 1 = X 2 = 20%and X 0 = 10%. The neutral of the generator is groundedthrough a reactor of 5% reactance based on the generatorrating. A double line-to-ground fault occurs at terminals band c. What is the current in the ground?
6- The sequence voltages are equal in a) LLL fault b) LL fault c) LG fault d) LLG fault. 7-In LL fault analysis a) Val=Vao b) Vai=Va2 c) Va2=Vao d) none of these
Q2 (1). In Figure 2-1, two curves represent fault currents supplied by two sources in case of phase faults at different corresponding locations. Overcurrent protection 1 and 2 are designed to protect line A- B. If there is no directional element, please explain how the setting values for overcurrent protection 1 and 2 could be calculated? (2). If only one directional element is available, please explain how the setting values for overcurrent protection 1 and 2 could be calculated? A B K1 IK1 g K2 Figure 2-1 IK2