**Question 21:**A multiple-choice quiz has 200 questions, each with 4 possible answers of which only 1 is correct. What is the probability that sheer guesswork yields more than 38 correct answers out of 100 problems which the student has no knowledge? [Hint: you may use the normal distribution to approximate the answer]

In this case, each of the answered questions has the only options of being "correct" (let's define…

Answered: Q21) A multiple-choice quiz has 200…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The amount of coffee that people drink per day is normally distributed with a mean of 15 ounces and a standard devilation of 5 ounces. 35 randomly selected people are surveyed. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X N b. What is the distribution of z? - N( c. What is the probability that one randomly selected person drinks between 14.6 and 15.3 ounces of coffee per day? d. For the 35 people, find the probability that the average coffee consumption is between 14.6 and 15.3 ounces of coffee per day. e. For part d), is the assumption that the distribution is normal necessary? Yes f. Find the IQR for the average of 35 coffee drinkers. No Q1 = ounces Q3 = ounces IQR: ounces
Solve the problem. A final exam in Math 160 has a mean of 73 with standard deviation 7.8. If 24 students are randomly selected, find the probability that the mean of their test scores is greater than 78. 0.0036 0.0008 0.0103 O 0.8962
q29
Find the probability that the average amount paid by the sample of households exceeds $50.
ANSWER IN T-DISTRIBUTION. A group of mathematics teachers wants to estimate the average computational skills of the students in senior high school. the standard deviation from the previous study is 5. how large must the sample be selected if they want to have 95% confidence of finding whether the true mean differs from the sample mean by 3.
You intend to conduct a goodness-of-fit test for a multinomial distribution with 5 categories. You collect data from 71 subjects. What are the degrees of freedom for the x² distribution for this test? d.f. = 85
Find the variance of x or the number of cups of coffee. (Do not round intermediate steps but round your final answer to 4 decimal places)
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According to a study done by UCB students, the height for Martian adult males is normally distributed with an average of 64 inches and a standard deviation of 2.3 inches. Suppose one Martian adult male is randomly chosen. Let X = height of the individual. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X - N( b. Find the probability that the person is between 62 and 63.9 inches. c. The middle 40% of Martian heights lie between what two numbers? Low: inches High: inches
Please tell me which of the multiple choice are correct A t-value of 2.35, from a t-distribution with 14 degrees of freedom, has an upper-tail (“greater than”) probability between which two values on the t-table?Select one:a. 2.15 and 2.26b. 0.29 and 0.82c. 0.025 and 0.01
A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether this distribution has changed, you randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the claimed or expected distribution? Use a=0.10. Complete parts (a) through (d). New Survey Frequency, f 111 97 Response Old Survey % Rewards 29% 23% Low rates Cash back Discounts Other 22% 108 8% 46 18% 63 UD. XX O D. X Xo 2 OC. X >Xo OC. X>x (c) Calculate the test statistic. (Round to three decimal places as needed.) %3D (d) Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim. V the claimed or ▼enough evidence to conclude that the distribution of motivations Ho At the 10% significance level, there expected distribution.
In a recent survey, approximately 90% of U.S. adults own a cell phone. Let's assume this can be modeled as a binomial distribution. In a group of 20 randomly selected adults, what is the standard deviation of the number of adults you would expect to own a cell phone? TTT Arial v T RBC 3 (12pt) Click Save and Submit to save and submit. Click Save All Answers to save all answers.

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