Q2.8 Question 1h Let G be an abelian group. Let H = {g € G | such that |g| < 0}. Then O H need not be a subgroup O H is always a subgroup but it need not be finite O H is always a finite subgroup

Q: 3.3 31 3 O 3 O 3평 37

A:

Q: 5. 8. 45°

A: Solve for value x

Q: 6.7 Find the unique number which is equal to its half plus 1.

A:

Q: 4. 108 45 C B.

A: As per guideline we have to solve only one since all question are different

Q: Is g = {(x, y) ∈ [−5, 5] × R : x^2 + y^2 = 25} a function from [−5, 5] to R.

A:

Q: 10

A: To simplify 35+710.

Q: 5.1 #7

A: Given that                  A=60-1054-403-3502-425, λ=5

Q: 1o.e 4.60

A: trigonometry rule

Q: 25. 1 | 1 1 + 1 - 1

A: Solution is done in step 2

Q: 4(2w-5) = 5w + 4 %3D

A:

Q: 10.0

A:

Q: T. 9

A: Given: To determine: ST→ &amp; tan∠S

Q: 18 20

A:

Q: 4.5-10

A: Introduction: Suppose X and Y follow the bivariate normal distribution with mean and variance of X…

Q: 1.6+0.4(x+6)+3.2

A: To simplify the expression means writing it in the simplest form.

Q: Find the value of x.

A: This can be solved using geometry and trigonometry rule.

Q: 20 9.

A:

Q: 29 14

A: It's trigonometric question so I'm providing hand written solution for better understanding.

Q: 1.r -5 1.Г 2

A:

Q: 10. 6. 3.

A: we have to find the radius of circle from the given figure

Q: 7. 45

A:

Q: 8. 2 k=1 3k

A:

Q: 60 6 30 V3/2

A: Topic:- trigonometry ratios

Q: 5. 20 52

A:

Q: 3. 18

A:

Q: Find the circumference of each circle. Leave your answer in terms of T.

A: From the image of the circle, we see that the radius=r=3.9 units

Q: 10 4 2.

A: Solution-

Q: | = +x 6.

A:

Q: 2.73-0.94

A: Here we subtract a number in another number.

Q: 3 33. 3 .2 3.

A:

Q: 14 19

A: To find :- x  Given :- Base = 14 , Hypotenuse = x ,               and θ= 49°   By using…

Q: 4(2w - 5) = 5w + 4 %3D

A: Here we have,  4(2w-5)=5w+4 ................................ (1)

Q: 7.) -3- %3D 10 2'

A: .

Q: 1. 12

A: We can use the concept of Pythagoras theorem to solve the given problem.

Q: 4. 36

A: Given,          34=a36