Q2. A three-phase ring main distributor ABCD, fed from point A and supplies balanced loads as follows: (1) 65A, 0.8 p.f. lagging at point B. (2) 90A, u.p.f. at point C. (3) 75A, 0.6 p.f. lagging at point D. The load currents being referred to the voltage at point A and the impedance per phase of the various line sections are: Section AB = (0.1+j0.1) 02/phase. Section BC= (0.1+j0.2) 02/phase. Section CD= (0.2+j0.1) 02/phase. Section DA= (0.2+j0.2) 02/phase. Determine the current in each section then find the source current (i,).
Q2. A three-phase ring main distributor ABCD, fed from point A and supplies balanced loads as follows: (1) 65A, 0.8 p.f. lagging at point B. (2) 90A, u.p.f. at point C. (3) 75A, 0.6 p.f. lagging at point D. The load currents being referred to the voltage at point A and the impedance per phase of the various line sections are: Section AB = (0.1+j0.1) 02/phase. Section BC= (0.1+j0.2) 02/phase. Section CD= (0.2+j0.1) 02/phase. Section DA= (0.2+j0.2) 02/phase. Determine the current in each section then find the source current (i,).
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:Q2. A three-phase ring main distributor ABCD, fed from point A and supplies
balanced loads as follows:
(1) 65A, 0.8 p.f. lagging at point B.
(2) 90A, u.p.f. at point C.
(3) 75A, 0.6 p.f. lagging at point D.
The load currents being referred to the voltage at point A and the impedance per
phase of the various line sections are:
Section AB = (0.1+j0.1) 02/phase.
Section BC= (0.1+j0.2) 02/phase.
Section CD= (0.2+j0.1) 12/phase.
Section DA= (0.2+j0.2) 02/phase.
Determine the current in each section then find the source current (i,).
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