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Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 120 and VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to Vce (sat). Vcc = 20 V Vo(V) Cutoff Vec Rc= I 3 14 kn Rp= 120 k2 o Vo Active V, ow VCE VBE (on) Vee (sat) = 1v Saturation 0 VeE (on) X v(V) Fig. 1(c)

Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 120 and VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to Vce (sat). Vcc = 20 V Vo(V) Cutoff Vec Rc= I 3 14 kn Rp= 120 k2 o Vo Active V, ow VCE VBE (on) Vee (sat) = 1v Saturation 0 VeE (on) X v(V) Fig. 1(c)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 120 and VBe (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to Vce (sat). Vcc = 20 V Vo(V) Cutoff Vcc Rc= 1.4 k2 Rp= 120 k2 o Vo Active V, oww VCE VBE (on) Vee (sat) = 1v 0 Ver (on) X Saturation v,(V) Fig. 1(c)
Transcribed Image Text:Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 120 and VBe (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to Vce (sat). Vcc = 20 V Vo(V) Cutoff Vcc Rc= 1.4 k2 Rp= 120 k2 o Vo Active V, oww VCE VBE (on) Vee (sat) = 1v 0 Ver (on) X Saturation v,(V) Fig. 1(c)
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