Q2) Find : (a) lim (2 + x) x-4+ 16-x 1-secx 0 sinx cos2x sintx (b) lim (c) lim (d) lim x-0 sin2x cos2x 4-x X cosx-sinx

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A:

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A:

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A: To find out the limit.

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A: Here we have to evaluate the given limit .

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A: Here we apply l Hopital's rule.

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A:

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A: Explained below

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Q: lim

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A: Given:        limθ→0sin2θtan3θθ2 Since we have an indeterminate form of type 00, we can apply the…

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A: Here we find limit