Q2) Find : (a) lim (2 + x) x-4+ 16-x 1-secx 0 sinx cos2x sintx (b) lim (c) lim (d) lim x-0 sin2x cos2x 4-x X cosx-sinx

Q: sinh(x)-sin(x) Find lim

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Q: Y = cos (2x). dr I given -4 when x = I 4 Find when x = dt Enter the exact answer. dy dt Number

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Q: →0 (2a−3/2a+ 5)^(2a+1) should i use lhopital or direct substitute the value of

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Q: lim2

A: Explained below

Q: lim (cos x)x² 1/x2

A:

Q: (12 sin )( In x) (x3+5)(x-1) Evaluate limx→1

A: Here we have to evaluate the given limit .

Q: 2 cos(8x) – 8 x² – 2 lim - sin(3x) — 2? — За

A: Here we apply l Hopital's rule.

Q: Find lim √√3x² + 3y² -1. (x,y) →(3,1) lim √√3x² + 3y² -1 = (x,y) →(3,1) (Type an exact answer.)

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Q: 3x2 + sin(x) lim x(x+ 5)

A: Given rational function is fx=3x2+sinxxx+5

Q: Evaluate (i) lim (1 – tan 6) sec 0

A:

Q: -2x² + x 41. g(x) y 3 - 1 -2 - 1 (a) lim g(x) (b) lim g(x) *→-' 1.

A: We will answer the first question as we don't answer multiple questions at a time. Please resubmit…

Q: Find the lim inf (xn) and lim sup (xn) of Xn=3-(-1)"

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Q: Зх + 1 1 lim x→0 sin x 5 2 3 1 2

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Q: Ex x-2 XE3, X-2 12) Consider メレ3 2) lim. (f(x) b) lim. (f(x)

A: Topic:- limit

Q: 1) lim X-2 2x-4n x(1-cosx) 2) lim х-0 tan(tan?x)

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Q: Q4 1-F(x)=limx→0 vV(x2+3)-3}/x2 2- limy 3y+5y2-7 10y3-11y+12 sin4x 3 - lim 0 sin2x

A:

Q: Guess the value of lim x 0 (tanx-x)/x3

A: Given :          limx→0tanx-xx3

Q: Evaluate: lim x→-1 x² + 2x + 1

A: Limit: Limit is a mathematical concept based on the concept of proximity that is used to give values…

Q: x+1-cos²(x) 3sin(x) 7. Find lim

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Q: (d) lim x/x

A: Given: Let y=limx→∞ x1x To Find: To evaluate the given limit.

Q: **. (1) lim,- V1+cos 2x 4 (x-) Q3) Find:

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Q: Find lim x→-3 sin(−4 π x)   lim x→-3 sin(−4 π x)

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Q: Name the method by determining whether I'Hôpital's Rule should be used or not. CSC x lim x+0+ √x

A: Need to write down the method to determine that l hospital is applicable or not.

Q: エ→2ー Prove that lim sin(1/x) does not exist. Lot II

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Q: lim as x goes to -3 of (4(2x+1)^2-100)/x+3

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Q: 2.r + x sin 3.x 1. lim * 5x - 2x +1

A: Here we find limit

Q: limx → 1 (x-2) / (x-1)2 ii.  limx → 1 (x2-1) / (x-1) iii. limx → 1  |x-1| / (x-1)

A: