2 cos(8x) – 8 x² – 2 lim - sin(3x) — 2? — За

Q: (2-4)* Q1: limx-1 sin(x³–1) x-1

A:

Q: 9. Lim 6x - Sin 2x メ→0 2x +3sin 4X b. lim x²-1 1/2

A:

Q: 2. Find if possible: sin(nx) a) lim x-4 x2-16 b) lim x (sinx+(cosx)³) (x2+1)(x-3) c) lim,--o (cosx)

A: a) Given that limx→-4sin(πx)x2-16we have to find the limit of…

Q: limx-->0 sin3x/ex-1

A:

Q: Find the limit: x->0  2 sin2 3x / 3x2

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Q: (2) 1: limx-1 sin(x3–1) x-1

A: limx→1 (2-1x)2sin(x3-1)x-1=limx→1 (2x-1x)2sin(x3-1)x-1=limx→1 4x2-4x+1x2sin(x3-1)x-1=limx→1…

Q: 1- cos(2x) lim x→0 х-0 1 — сos(6х) 7* – 6* – 1 lim x→1 х2 — 1

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Q: lim cos x+4e* is 5er

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Q: 1+x V1-x sin-1(x) [3] limx-0

A: To evaluate: lim[x→01+x-1-xsin-1(x)] Solution: lim[x→01+x-1-xsin-1(x)] On simplifying further we…

Q: 1 2. lim cOs X -

A: The given function rewrite as

Q: (1 cosr)dt 1. limx-0 2x -?

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Q: -lim COS X tanx <-2メ X-8 2 lim 3 x→2 x42x +X-2 A

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Q: lim 0 3x²+5 cos x- 2x -5

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Q: lim (cos(9x)) (+) x-0+

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Q: 1-cos 2x lim x→0 x2

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 6x-sin 2x 2x+3sin 4x 15. lim

A: Since you have asked multiple questions in single request. So we will answering only first question.

Q: 2x -cos(2x)- 2x - (b) lim | x2

A:

Q: Compute 1) Lim X-3.9טTX 2) um X-71T sin x TT-X 3) um -X. X2-X-6

A: (1) The given expression of limit is

Q: In(cos ax) limx-0 ? In(cos bx)

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Q: tan 3x 18. lim 1-cos x 19. lim -0 tanx

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Q: 2ェ+ COS lim エ→ー 3.x - Vz?+3

A: I=limx→-∞2x+cosx3x-x2+3dividing x b N and…

Q: 1-coskx 2. lim = 0. kx

A: We have to find the limit of the function (1-coskx)/kx when x tends to 0 .

Q: why is limx->0[x^4 * cos(2/3x)] not equal to zero? I thought that if I plug in zero to x^4 it makes…

A: Given that: limx→0x4.cos23x

Q: b) lim sin(x² – 4) х* -16 2х - 3 а) lim %3D V3x² +16 x->2 X->-0

A:

Q: Evaluate: lim   (1−cos−1x)csch(1−x) x→1−

A: We have to find the limit.

Q: (1) lim,o In (sec x) 3x (2) lim, (tan x)*

A:

Q: 1 3. lim coS x 14. x-0 5. lim 4x+7

A: Given query is to find indicated limits.

Q: 2 lim(cosx)x² =? x→0

A: Given: limx→0cosx2x2=limx→0cos2x2x

Q: 5. Evaluate: lim, 0 2x- x2 sin a 1 Does not exist 2.

A: lim (2x-x2)/sinxx→0

Q: cos x-2sinx 1. limx-n 3cosx -2 limx-3 X-3 3x6-x*+2x-3 limy--o 4x5+2x3-5 iv. lim,→-1(x³ limy--1(x³ –…

A: [i]

Q: 2tan 'x -x (-) 2x – sin 'x 02. lim, -1

A: Given limx→02tan-1x-x2x-sin-1xTo evaluate the limit:

Q: (1) lim,-0 √x+9-3 X (2) lim-0 1–c05x x sinx (3) limx-1 x²+3x-4 x-1

A:

Q: 1) lim-sinxr x-0

A: given equation is     limx--&gt;0  (x-sinx) / x³ ** L hospital rule =&gt;    limx--&gt;0  f(x) /…

Q: 7- sin-(e*) 2 lim V1 - e2x

A:

Q: find lim x-> 0, cos (12x)-1 / 3x

A: Given,              limx→0cos 12x - 13x Move the term 1/3 outside of the limit because it is…

Q: Q3 :(A): By using " L' Hopital rules "; Find the limits of: 1 (1) limx-o[: 1-cos x 2 sin²x (2)…

A: We have to find the limit using L Hospital rule.

Q: 3 lim tan³ 2x x→0

A:

Q: 2. Evaluate cosxsin2x lim 1 – sinx

A: We need to find limx→π2cos x sin 2x1-sin x Now, put the limit in the function, that is put x=π2 .…

Q: In cos 2.x 4. Find lim -0 In cos 3x

A: limx→0ln (cos 2x)ln(cos 3x)Applying L'hospital rule:= limx→0ddxln(cos 2x)ddxln(cos 3x)= limx→0…

Q: 1-cos (4x) e) lim x0 2-2cos (6x) (x+1)2 + (2x+3)³ 3x2(8x+1) h) lim X00

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Q: 1. lim ux-121 X-3

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Q: 7x( cos (4x) – 1) Use l'Hôpital's Rule to evaluate lim sin (5x) – 5x

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Q: 2tan x- x lim, -1 2х -sin " x,

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Q: 2х а) lim -1-2x (sin 2x)+² - et b) lim -4x - cos x

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Q: cos(x) lim COS 21

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Q: limx¬1 x(1 – cos-) x→1

A:

Q: lim- XVx 1 5 arctan 4 arctan 5 ? Use L'Hospital's Rule 4

A: