Q2: Equipment ratings for the four power system shown in Figure (1) are as follow: - GI 500 MVA, 13.8 kV, X = 0.2 p.u G2-750 MVA, 18 kV, X-0.18 p.u G3-1000 MVA, 20 kV, X-0.17 p.u TI = 500 MVA, 13.8/500 kV, XT1 0.12 p.u T2 750 MVA, 18/500 kV, XT2= 0.1 p.u T3-1000 MVA, 20/500 kV, XT3-0.1 p.u. (1) T1 T3 T.L1 G1 j50 ohm 13,8/500 KV 20/500 kV T.L 2 j50 ohm T.L 3 j50 ohm T2 G3 18/500 KV G2 Figure (1) neglecting resistance, transformer phase shift, and magnetizing reactance, draw the positive - sequence reactance diagram on a 1000 MVA, 20kV base in the G3.

E2(V) 120V Test Open-circuit Short- circuit Primary 12(A) .29A 2A P2(W) 8.78W 13.4W 6.85V E1(V) P1(W) 7.69W 13.14W Test Open-circuit Short- circuit 11(A) .62A SA 48V 2.83V Normal 12 at E1 11 P1 E2 12 P2 120V 50.6V 48.42V 48.8V 49.33V 182A 4A 6A 815A 1A 1.22A 142A .2 4.75A 237.4W 56.5W 120.3V 1.31A 1.77A 2.28A 2.73A 3.26А 3.74A 119.6V 119.8V 120.6V 119.4V 120.6V 120.1V 119.9V 120.3V 219.1W 48.3W 72.39W 98.3W 120.1W 146.9W .4 81.2W 108.2W 130.5W 159.2W 184W 209.2W 237.5W .8 49.1V 1.2 1.4 49.83V 49.91V 50.1V 50.55V 170W 193.6W 219.1W 238.1W 1.6 4.23A 1.616A 1.8 4.74A 1.82A 2.0 50.3V 5.18A 258.3W 119.1V 2A 1) Calculate the turns ratio from the transformer primary/secondary voltage ratinga a= Using the open-circuit data at the primary and the short-circuit data at the secondary, calculate the four transformer parameters (to 3 significant figures) and fill in the following table. Parameter Rel Value(ohm) Xel Rc1 Xm1 Using the open-circuit data at the secondary and the short-circuit data at…

A 107 hp, 257 V de shunt motor has the magnetization curve in the graph. The armature circuit resistance, including brushes, is .032 ohm. no load rotational losses are 2087 w and the stray loss is 1% of the output The field rheostat is adjusted for a no-load speed of 1107 pm a. What would be the field current at no load when speed is 1100 rpm b. Determine Speed and output in horsepower corresponding to an armature current of 400A c. Now a cumulative series turns 2 (N) per pole is to be added with R negligible and 1000 turns in Shunt field find speed corresponding to an armature current of 400A

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