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- Among private universities in the United States, the mean ratio of students to professors is 35.2 (i.e., 35.2 students for each professor) with a standard deviation of 8.8. Suppose a random sample of 50 universities is selected and the observed mean student-to-professor ratio is 38. Is there evidence that the reported mean ratio actually exceeds 35.2? Use = 0.05 and conduct the appropriate hypothesis test. ( See attached picture )What is a Type II error? a. Ho is rejected and there is an effect b. Ho is rejected but there is no effect c. Ho is retained but there is an effect d. The wrong standard deviation is calculated.A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,722. Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of $49,870 and a standard deviation of $3900. Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722? Ho: μ = Ha: (Put in the correct symbol and value) ✓ Select an answer a not = P-value: = ↑ Based on the above we choose to Select an answer Question Help: Post to forum Submit Question
- The average number of accidents at controlled intersections per year is 5.6. Is this average a different number for intersections with cameras installed? The 67 randomly observed intersections with cameras installed had an average of 5.8 accidents per year and the standard deviation was 0.6. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer v H1: ? v Select an answer V c. The test statistic ? V = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. The data suggest that the population mean is not significantly different from 5.6 at a = 0.01, so there is statistically insignificant evidence to conclude that the population mean number of accidents per year at…(b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by √n The p-value is the area under the curve to the right of the value of the test statistic. O One-tailed o Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. Step 4: Enter the p- value. (Round to 3 decimal places.) 0.3 0.2 0.1 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the studio. o Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean player rating is higher than 90. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean player rating is higher than 90.…Suppose the national average dollar amount for an automobile insurance claim is $670.543. You work for an agency in Michigan and you are interested in whether or not the state average is different from the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ = 670.543, Alternative Hypothesis: μ ≠ 670.543. A random sample of 27 claims shows an average amount of $668.645 with a standard deviation of $68.6867. What is the test statistic and p-value for this test? Question 8 options: 1) Test Statistic: -0.144, P-Value: 0.44345 2) Test Statistic: -0.144, P-Value: 0.5566 3) Test Statistic: -0.144, P-Value: 1.5566 4) Test Statistic: 0.144, P-Value: 0.8869 5) Test Statistic: -0.144, P-Value: 0.8869
- The average salary for American college graduates is $44,300. You suspect that the average is different for graduates from your college. The 61 randomly selected graduates from your college had an average salary of $44,099 and a standard deviation of $4,460. What can be concluded at the a = 0.10 level of significance? a. For this study, we should useSelect an answer b. The null and alternative hypotheses would be: Họ: vSelect an answer H: ? vSelect an answer c. The test statistic (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is va the null hypothesis. f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... O The data suggest that the population mean is not significantly different from 44,300 at a = 0.10, so there is statistically insignificant evidence to conclude that the population mean salary for graduates from your college is different from 44,300. The data suggest that…The mean number of eggs per person eaten in the United States is 244. Do college students eat a different number of eggs than the average American? The 60 college students surveyed averaged 255 eggs per person and their standard deviation was 64.4. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Но: 244 H1: PV A 244 c. The test statistic 1.323 (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? Va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest that the populaton mean is significantly different from 244 at a = 0.10, so there is statistically significant evidence to conclude that the population mean number of eggs consumed by college students per year is different from 244. O The data suggest that the…A survey using a sample size of 11 reveals that the average size of dairy farms in Simcoe County is 1500 hectares with a standard deviation of 150 hectares. As a researcher, you take this information and conduct a hypothesis test and find the calculated value of the test statistic is 2.2. Prior to the study, the following hypotheses were established: но: и - 1400 H1: u > 1400 Use a = 0.01. Based on the test statistic and sample size, what the p-value is so we should the null hypothesis. _(0.0262, .0262, 0.026, .026) Given that the p-value is (greater/less) (greater, larger, >, bigger) than a, we should (accept/reject) _ lаccept) the null hypothesis. 0.062, reject ) 0.0131, accept 0.0026, reject ) 0.0262, accept 0.062, accept
- A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,722. Suppose that a random sample of 50 accounting graduates ata large university who received job offers resulted in a mean offer of $49.870 and a standard deviation of $3900, Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722? Ho: = H: p Select an answerY (Put in the correct syimbol and value) P value Based on the above we choose to Select an answerRecords indicate that the mean weight of mature rainbow trout in Eagle Creek is 2.25 kg with a standard deviation of 0.53 kg. After years of marked oxygen depletion from pollutants in the creek, you want to perform a hypothesis test to see if the standard deviation, σ, of weights has changed. To do so, you measure the weights of 16 randomly chosen mature rainbow trout from the creek and find that the sample standard deviation is 0.34 kg. Under the assumption that current weights of mature rainbow trout in the creek follow a normal distribution, you will perform a chi-square test.Find χ2, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places.=χ2suppose that for a sexually active male drosophila fruit fly in a particular genetics lab the population mean lifespan is 38.9 days with a population standard deviation of 12.0 days when she experimentally removed all females from a simple random sample of 24 this drosophila flies in her lab a researcher in the slab found that 24 sexually inactive males had a mean lifespan of 62.5 days with a standard deviation of 14.1 days answer the questions below about the experiment and about testing weather sexual activity affects how long males Drosophila live. How do you find the Critical Value? How do you find theP-Value? reject or fail to reject the null hypothesis?