(Q18) A titanium cation with a charge of +3 can form a complex with six water molecules: [Ti(H2O)6]**. If one of the six water molecules is deprotonated (donating its proton to a water molecule in solution) what will be the formula of the complex that remains? O [Ti(OH)6]4- O [Ti(H20)5(OH)]²+ O [Ti(H2O)4(OH)2]* O [Ti(H2O)6(OH)21* O [Ti(OH)6]³-

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(Q18) A titanium cation with a charge of +3 can form a complex with six water molecules:
[Ti(H20)613+. If one of the six water molecules is deprotonated (donating its proton to a water
molecule in solution) what will be the formula of the complex that remains?
O [Ti(OH)6]4-
O [Ti(H2O)5(OH)]²+
O [Ti(H2O)4(OH)2]*
O [Ti(H2O)6(OH)2]*
O [Ti(OH)6]³-
Transcribed Image Text:(Q18) A titanium cation with a charge of +3 can form a complex with six water molecules: [Ti(H20)613+. If one of the six water molecules is deprotonated (donating its proton to a water molecule in solution) what will be the formula of the complex that remains? O [Ti(OH)6]4- O [Ti(H2O)5(OH)]²+ O [Ti(H2O)4(OH)2]* O [Ti(H2O)6(OH)2]* O [Ti(OH)6]³-
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