Q15) Given that y₁ (t) = t¹ is solution for 2t2y" + ty' - 3y = 0,t> 0, then y₂ (t) is: a) t b) tz e-at sin3t atsinst Q16) L-¹ (5-3)²+25) d) = a) estsinst 5 est sin3t 5 b) 5 5 18
Q15) Given that y₁ (t) = t¹ is solution for 2t2y" + ty' - 3y = 0,t> 0, then y₂ (t) is: a) t b) tz e-at sin3t atsinst Q16) L-¹ (5-3)²+25) d) = a) estsinst 5 est sin3t 5 b) 5 5 18
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.4: Multiple-angle Formulas
Problem 50E
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![Q15) Given that y₁ (t) = t¹ is solution for 2t²y" + ty' - 3y = 0,t> 0, then y₂ (t) is:
a) t
b) tz
atsinst
Q16) L-¹ (5-3)²+25)
est sinst
e-at sin3t
5
d)
=
est sin3t
5
a)
b)
5
5
18](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff642c1e3-2750-4de6-b32d-528cbede41a7%2Fc6bd4845-0135-4858-bf6e-204a250f165d%2Fqi60k6d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q15) Given that y₁ (t) = t¹ is solution for 2t²y" + ty' - 3y = 0,t> 0, then y₂ (t) is:
a) t
b) tz
atsinst
Q16) L-¹ (5-3)²+25)
est sinst
e-at sin3t
5
d)
=
est sin3t
5
a)
b)
5
5
18
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