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Q11. The DE (xy² + x − 2y + 3)dx − x²ydy = 2(x + y)dy, y(1) = 1 when express in terms of Mdx + Ndy = 0 is a) (xy2 + x-2y+3)dx- (x²y-2x-2y)dy = 0 Option 1 c) (xy² +x+2y-3)dx − (x²y − 2x + 2y)dy = 0 Option 3 b) (xy²-x+2y-3)dx − (x²y + 2x - 2y)dy = 0 O Option 2 d) (xy² + x - 2y + 3)dx + (x²y − 2x − 2y)dy = 0 O Option 4

Q11. The DE (xy² + x − 2y + 3)dx − x²ydy = 2(x + y)dy, y(1) = 1 when express in terms of Mdx + Ndy = 0 is a) (xy2 + x-2y+3)dx- (x²y-2x-2y)dy = 0 Option 1 c) (xy² +x+2y-3)dx − (x²y − 2x + 2y)dy = 0 Option 3 b) (xy²-x+2y-3)dx − (x²y + 2x - 2y)dy = 0 O Option 2 d) (xy² + x - 2y + 3)dx + (x²y − 2x − 2y)dy = 0 O Option 4

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Q11. The DE (xy² + x − 2y + 3)dx − x²ydy = 2(x + y)dy, y(1) = 1 - when express in terms of Mdx + Ndy = 0 is a) (xy²+x-2y+3)dx- (x²y - 2x - 2y)dy = 0 Option 1 c) (xy² +x+2y-3)dx- (x²y-2x + 2y)dy = 0 Option 3 b) (xy²-x+2y-3)dx − (x²y + 2x - 2y)dy = 0 O Option 2 d) (xy² + x - 2y + 3)dx + (x²y − 2x − 2y)dy = 0 O Option 4
Transcribed Image Text:Q11. The DE (xy² + x − 2y + 3)dx − x²ydy = 2(x + y)dy, y(1) = 1 - when express in terms of Mdx + Ndy = 0 is a) (xy²+x-2y+3)dx- (x²y - 2x - 2y)dy = 0 Option 1 c) (xy² +x+2y-3)dx- (x²y-2x + 2y)dy = 0 Option 3 b) (xy²-x+2y-3)dx − (x²y + 2x - 2y)dy = 0 O Option 2 d) (xy² + x - 2y + 3)dx + (x²y − 2x − 2y)dy = 0 O Option 4
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