Q10. The current (in A) passes through the cross section of bridge's wire for equilibrium state (le = 0) equals: A) 0.17 B) 0.40 C) 0.10 D) 0.24 E) 0.45
Q10. The current (in A) passes through the cross section of bridge's wire for equilibrium state (le = 0) equals: A) 0.17 B) 0.40 C) 0.10 D) 0.24 E) 0.45
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Q 10 please
![Q5. In the circuit shown if the wire used was Las 100 cm long,
E=1.2 V, R-2 kn, R-3 kf, and the balance point C is for
LAC 45 cm, then the resistance R, (in KM) is:
A) 7.50
D) 8.32
R₂
A) ACR
Q6. If the current, in the circuit shown beside, passes from
point D to point C, then for the ratio Lac/Les
LcB R₂
LAC
D):
B) 1.25
E) 0.50
LcB
R₂
R₂
B)
C) 4.09
LAC-R
=
LcB R₂
E)
LCB
Les
For the circuit shown, the power dissipated in the load
resistance R₂ is given as a function of R.
Q7. The electromotive force & (in V) is:
A) 2.40 B) 1.10 C) 3.37 D) 1.96
E) 1.70
Q8. The power delivered to the resistance 30 when R₂ equals
40 (in mW) is:
A) 18.0 B) 9.0
C) 13.5 D) 32.3 E) 27.0
In the circuit shown, if the length of the potentiometer
LAB 100 cm and the current in the galvanometer was zero for
LAC-33 cm and the resistance of the bridge's wire is 5
Q9. The emf of unknown battery &, (in Volts) is:
A) 0.9 B) 0.7 C) 0.1 D) 0.3 E) 0.4
Q10. The current (in A) passes through the cross section of
bridge's wire for equilibrium state (le = 0) equals:
A) 0.17 B) 0.40 C) 0.10 D) 0.24 E) 0.45
24
4
R
A (mm)
D
-#-
N
M
20 40 60 80 100
R
300
N
8₂](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48ed58b1-dcb7-4b16-9209-abaf1a4086d3%2F328c8593-29af-4839-ae3c-b864a3740579%2Fups78r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q5. In the circuit shown if the wire used was Las 100 cm long,
E=1.2 V, R-2 kn, R-3 kf, and the balance point C is for
LAC 45 cm, then the resistance R, (in KM) is:
A) 7.50
D) 8.32
R₂
A) ACR
Q6. If the current, in the circuit shown beside, passes from
point D to point C, then for the ratio Lac/Les
LcB R₂
LAC
D):
B) 1.25
E) 0.50
LcB
R₂
R₂
B)
C) 4.09
LAC-R
=
LcB R₂
E)
LCB
Les
For the circuit shown, the power dissipated in the load
resistance R₂ is given as a function of R.
Q7. The electromotive force & (in V) is:
A) 2.40 B) 1.10 C) 3.37 D) 1.96
E) 1.70
Q8. The power delivered to the resistance 30 when R₂ equals
40 (in mW) is:
A) 18.0 B) 9.0
C) 13.5 D) 32.3 E) 27.0
In the circuit shown, if the length of the potentiometer
LAB 100 cm and the current in the galvanometer was zero for
LAC-33 cm and the resistance of the bridge's wire is 5
Q9. The emf of unknown battery &, (in Volts) is:
A) 0.9 B) 0.7 C) 0.1 D) 0.3 E) 0.4
Q10. The current (in A) passes through the cross section of
bridge's wire for equilibrium state (le = 0) equals:
A) 0.17 B) 0.40 C) 0.10 D) 0.24 E) 0.45
24
4
R
A (mm)
D
-#-
N
M
20 40 60 80 100
R
300
N
8₂
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