Q1.The shaft, as shown in Fig. , is driven by pulley B from an electric motor. Another belt drive from pulley A is running a compressor. The ratio of belt tensions for pulley A is r. The belt tensions for pulley B are TB1 N and TB2 N. The diameter of pulley A is DA mm and the diameter of pulley B is DB mm. The weight of pulley A and B is WA N and WB N. The allowable tensile stress for the shaft material is 180 MPa and the allowable shear stress is 90 MPa. Taking torsion and bending factors as 1.2 and 1.8 respectively, find the shaft diameter. 100-→150 e100- All dimensions in mm. r= 3 TB1= 1410 TB2= 470 DA= 168 DB= 476 WA= 388 WB= 1100

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Q1.The shaft, as shown in Fig. , is driven by pulley B from an electric motor.
Another belt drive from pulley A is running a compressor. The ratio of belt
tensions for pulley A is r. The belt tensions for pulley B are TB1 N and TB2 N. The
diameter of pulley A is DA mm and the diameter of pulley B is DB mm. The weight
of pulley A and B is WA N and WB N. The allowable tensile stress for the shaft
material is 180 MPa and the allowable shear stress is 90 MPa. Taking torsion and
bending factors as 1.2 and 1.8 respectively, find the shaft diameter.
B
B
-100-150-100-
T
All dimensions in mm.
r= 3 TB1= 1410 TB2= 470
DA= 168 DB= 476 WA= 388
WB= 1100
Transcribed Image Text:Q1.The shaft, as shown in Fig. , is driven by pulley B from an electric motor. Another belt drive from pulley A is running a compressor. The ratio of belt tensions for pulley A is r. The belt tensions for pulley B are TB1 N and TB2 N. The diameter of pulley A is DA mm and the diameter of pulley B is DB mm. The weight of pulley A and B is WA N and WB N. The allowable tensile stress for the shaft material is 180 MPa and the allowable shear stress is 90 MPa. Taking torsion and bending factors as 1.2 and 1.8 respectively, find the shaft diameter. B B -100-150-100- T All dimensions in mm. r= 3 TB1= 1410 TB2= 470 DA= 168 DB= 476 WA= 388 WB= 1100
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