Q1.) A CRT deflection plates of (60mm) long and (0.5cm) apart. The screen is (22cm away from the center of deflection plates. The electrons enter the plates with velocity o (2.445x10'm/sec). If an input signal is applied, it will produce (3cm) deflection on the scree with an angular deflection of (7.77°). Determine: 1- Acceleration voltage. 2- Deflection potential. 3- The coordinate of electrons beam at the center of deflection plates. 4- The time taken by electrons beam in its traveling from the end of deflection plates to th screen. Note: m= 9.1x10'kg e=1.6x10l°C

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Q1.) A CRT deflection plates of (60mm) long and (0.5cm) apart. The screen is (22cm
away from the center of deflection plates. The electrons enter the plates with velocity o
(2.445x10'm/sec). If an input signal is applied, it will produce (3cm) deflection on the scree
with an angular deflection of (7.77°). Determine:
1- Acceleration voltage.
2- Deflection potential.
3- The coordinate of electrons beam at the center of deflection plates.
4- The time taken by electrons beam in its traveling from the end of deflection plates to th
screen.
Note:
m= 9.1x10'kg
e=1.6x10l°C
Transcribed Image Text:Q1.) A CRT deflection plates of (60mm) long and (0.5cm) apart. The screen is (22cm away from the center of deflection plates. The electrons enter the plates with velocity o (2.445x10'm/sec). If an input signal is applied, it will produce (3cm) deflection on the scree with an angular deflection of (7.77°). Determine: 1- Acceleration voltage. 2- Deflection potential. 3- The coordinate of electrons beam at the center of deflection plates. 4- The time taken by electrons beam in its traveling from the end of deflection plates to th screen. Note: m= 9.1x10'kg e=1.6x10l°C
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We are authorized to answer three subparts at a time since you have not mentioned which part you are looking for, so we are answering the first three subparts, please repost your question separately for the remaining subpart.

1-

At any moment, the kinetic energy of the electron will be equal to its potential energy. From the calculation, we can determine the acceleration voltage as shown below: 

Electrical Engineering homework question answer, step 1, image 1

The acceleration voltage is 1700 Volts

Step 2

2-

The deflection potential is given by the expression as shown below: 

Electrical Engineering homework question answer, step 2, image 1

Plugging the values in the above expression, 

Electrical Engineering homework question answer, step 2, image 2

 

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