Q1/ Water flow through an orifice meter at an empirical equation Re 0.35RE0 and a rate of 300*10° m/s, what will be the difference in pressure head across the meter. Note that : %3D 0.9m. Re= 5095.53 Ca= 0.61 g= 9.81m/s? p=1000 kg/m u = 1*10* kg/m.s m'=Mass flow rate G=Mass flux Re0= Reynolds number at orifice meter
Q1/ Water flow through an orifice meter at an empirical equation Re 0.35RE0 and a rate of 300*10° m/s, what will be the difference in pressure head across the meter. Note that : %3D 0.9m. Re= 5095.53 Ca= 0.61 g= 9.81m/s? p=1000 kg/m u = 1*10* kg/m.s m'=Mass flow rate G=Mass flux Re0= Reynolds number at orifice meter
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Q1/ Water flow through an orifice meter at an empirical equation Re = 0.35RE0
and a rate of 300*10* m/s, what will be the difference in pressure head across the meter.
Note that :
%3D
-
0.9m.
Re=5095.53
Ca= 0.61
g= 9.81m/s
p=1000 kg/m
u = 1*10* kg/m.s
m'=Mass flow rate
%3D
G=Mass flux
Re0= Reynolds number at orifice meter](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4488d463-865f-42f9-90e2-d41317d81ecd%2Fdd792aa3-85aa-4944-b959-a6c83ea299cc%2Feo59woc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:G
Q1/ Water flow through an orifice meter at an empirical equation Re = 0.35RE0
and a rate of 300*10* m/s, what will be the difference in pressure head across the meter.
Note that :
%3D
-
0.9m.
Re=5095.53
Ca= 0.61
g= 9.81m/s
p=1000 kg/m
u = 1*10* kg/m.s
m'=Mass flow rate
%3D
G=Mass flux
Re0= Reynolds number at orifice meter
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