Q1: The spring is undeformed (unstretched) when x = 0. If the body moves from the initial position x1 = 100 mm to the final position x2 = 200 mm, determine: 1- The work done by the spring on the body 2- The work done on the body by its weight. [ Ans.: U, = -60 J, Uw = 2.35 J]
Q1: The spring is undeformed (unstretched) when x = 0. If the body moves from the initial position x1 = 100 mm to the final position x2 = 200 mm, determine: 1- The work done by the spring on the body 2- The work done on the body by its weight. [ Ans.: U, = -60 J, Uw = 2.35 J]
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Subject: Eng. Mech. Dynamics I
Tutorial Sheet 5
University of Babylon
Kinetics of particles
"Work and Energy"
Class: 2nd
College of Engineering/Al-Musayab
Lecturer: Mushrek A. Mahdi
30
Q1: The spring is undeformed (unstretched) when
x = 0. If the body moves from the initial position
x, = 100 mm to the final position x2 = 200 mm,
determine:
2 lb
15
1- The work done by the spring on the body
2- The work done on the body by its weight.
[ Ans.: U, = -60 J, Uw = 2.35 J]
Q4: The system is released from rest with no
slack in the cable and with the spring
4 kN/m
www
unstretched. Determine the distanced s traveled
by the 10-kg cart before it comes to rest (a) if m
approaches zero and (b) if m = 2 kg Assume no
mechanical interference
7 kg
[ Ans.: (a) s = 0. 663 m, (b) s = 0.349 m]
20
10 kg
25
Q2: The 64.4-lb crate slides down the curved path
in the vertical plane. If the crate has a velocity of 3
ft/sec down the incline at A and a velocity of 25
ft/sec at B, compute the work U, done on the crate
by friction during the motion from A to B.
k = 125 N/m
[Ans.: Uf =-672 lb. ft ]
3 ft/sec
Q5: The 2-kg collar is released from rest at A and
slides down the inclined fixed rod in the vertical
plane. The coefficient of kinetic friction is 0.40.
Calculate (1) the velocity v of the collar as it strikes
the spring and (2) the maximum deflection x of the
spring.
20
B 25 ft/sec
[ Ans.: (1) v = 2.56 m/s, x = 98.9 mm]
Q3: The 1.5-lb collar slides with negligible friction
on the fixed rod in the vertical plane. If the collar
2 kg
starts from rest at A under the action of the constant
0.5 m
2-lb horizontal force, calculate its velocity v
as it hits the stop at B.
Hp =0.40
[ Ans.: (1) v = 17. 18 ft/s]
k = 1.6 kN/m
60](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2157ad6-224b-48c8-a770-6788030328d6%2F9dde750a-d939-4000-bbd6-e7efcb3305f2%2Ftgdsccb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Subject: Eng. Mech. Dynamics I
Tutorial Sheet 5
University of Babylon
Kinetics of particles
"Work and Energy"
Class: 2nd
College of Engineering/Al-Musayab
Lecturer: Mushrek A. Mahdi
30
Q1: The spring is undeformed (unstretched) when
x = 0. If the body moves from the initial position
x, = 100 mm to the final position x2 = 200 mm,
determine:
2 lb
15
1- The work done by the spring on the body
2- The work done on the body by its weight.
[ Ans.: U, = -60 J, Uw = 2.35 J]
Q4: The system is released from rest with no
slack in the cable and with the spring
4 kN/m
www
unstretched. Determine the distanced s traveled
by the 10-kg cart before it comes to rest (a) if m
approaches zero and (b) if m = 2 kg Assume no
mechanical interference
7 kg
[ Ans.: (a) s = 0. 663 m, (b) s = 0.349 m]
20
10 kg
25
Q2: The 64.4-lb crate slides down the curved path
in the vertical plane. If the crate has a velocity of 3
ft/sec down the incline at A and a velocity of 25
ft/sec at B, compute the work U, done on the crate
by friction during the motion from A to B.
k = 125 N/m
[Ans.: Uf =-672 lb. ft ]
3 ft/sec
Q5: The 2-kg collar is released from rest at A and
slides down the inclined fixed rod in the vertical
plane. The coefficient of kinetic friction is 0.40.
Calculate (1) the velocity v of the collar as it strikes
the spring and (2) the maximum deflection x of the
spring.
20
B 25 ft/sec
[ Ans.: (1) v = 2.56 m/s, x = 98.9 mm]
Q3: The 1.5-lb collar slides with negligible friction
on the fixed rod in the vertical plane. If the collar
2 kg
starts from rest at A under the action of the constant
0.5 m
2-lb horizontal force, calculate its velocity v
as it hits the stop at B.
Hp =0.40
[ Ans.: (1) v = 17. 18 ft/s]
k = 1.6 kN/m
60
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