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Q1: The spring is undeformed (unstretched) when x = 0. If the body moves from the initial position x1 = 100 mm to the final position x2 = 200 mm, determine: 1- The work done by the spring on the body 2- The work done on the body by its weight.

Q1: The spring is undeformed (unstretched) when x = 0. If the body moves from the initial position x1 = 100 mm to the final position x2 = 200 mm, determine: 1- The work done by the spring on the body 2- The work done on the body by its weight.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Subject: Eng. Mech. Dynamics I Tutorial Sheet 5 University of Babylon Kinetics of particles "Work and Energy" Class: 2nd College of Engineering/Al-Musayab Lecturer: Mushrek A. Mahdi 30 Q1: The spring is undeformed (unstretched) when x = 0. If the body moves from the initial position x, = 100 mm to the final position x2 = 200 mm, 2 lb determine: 15 1- The work done by the spring on the body 2- The work done on the body by its weight. [ Ans.: U, = -60 J, Uw = 2.35 J] www Q4: The system is released from rest with no slack in the cable and with the spring 4 kN/m unstretched. Determine the distanced s traveled by the 10-kg cart before it comes to rest (a) if m approaches zero and (b) if m = 2 kg Assume no mechanical interference 7 kg [ Ans.: (a) s = 0. 663 m, (b) s = 0.349 m] 20 Q2: The 64.4-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of 3 ft/sec down the incline at A and a velocity of 25 ft/sec at B, compute the work U, done on the crate by friction during the motion from A to B. 25 k = 125 N/m [Ans.: Uf = -672 lb. ft ] 3 ft/sec Q5: The 2-kg collar is released from rest at A and slides down the inclined fixed rod in the vertical plane. The coefficient of kinetic friction is 0.40. Calculate (1) the velocity v of the collar as it strikes the spring and (2) the maximum deflection x of the spring. 20 B 25 ft/sec [ Ans.: (1) v = 2.56 m/s, x = 98.9 mm] Q3: The 1.5-lb collar slides with negligible friction on the fixed rod in the vertical plane. If the collar starts from rest at A under the action of the constant 2 kg 0.5 m 2-lb horizontal force, calculate its velocity v as it hits the stop at B. Hq = 0.40 [ Ans.: (1) v = 17.18 ft/s] k = 1.6 kN/m 60
Transcribed Image Text:Subject: Eng. Mech. Dynamics I Tutorial Sheet 5 University of Babylon Kinetics of particles "Work and Energy" Class: 2nd College of Engineering/Al-Musayab Lecturer: Mushrek A. Mahdi 30 Q1: The spring is undeformed (unstretched) when x = 0. If the body moves from the initial position x, = 100 mm to the final position x2 = 200 mm, 2 lb determine: 15 1- The work done by the spring on the body 2- The work done on the body by its weight. [ Ans.: U, = -60 J, Uw = 2.35 J] www Q4: The system is released from rest with no slack in the cable and with the spring 4 kN/m unstretched. Determine the distanced s traveled by the 10-kg cart before it comes to rest (a) if m approaches zero and (b) if m = 2 kg Assume no mechanical interference 7 kg [ Ans.: (a) s = 0. 663 m, (b) s = 0.349 m] 20 Q2: The 64.4-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of 3 ft/sec down the incline at A and a velocity of 25 ft/sec at B, compute the work U, done on the crate by friction during the motion from A to B. 25 k = 125 N/m [Ans.: Uf = -672 lb. ft ] 3 ft/sec Q5: The 2-kg collar is released from rest at A and slides down the inclined fixed rod in the vertical plane. The coefficient of kinetic friction is 0.40. Calculate (1) the velocity v of the collar as it strikes the spring and (2) the maximum deflection x of the spring. 20 B 25 ft/sec [ Ans.: (1) v = 2.56 m/s, x = 98.9 mm] Q3: The 1.5-lb collar slides with negligible friction on the fixed rod in the vertical plane. If the collar starts from rest at A under the action of the constant 2 kg 0.5 m 2-lb horizontal force, calculate its velocity v as it hits the stop at B. Hq = 0.40 [ Ans.: (1) v = 17.18 ft/s] k = 1.6 kN/m 60
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