Q1- The magnetic circuit shown is made of a cast-steel and has a coil of 1000 turns on its center limp. The center limp and each of the side limbs has a width of 5cm and the t =5 cm . The means length of magnetic paths limp=30 Determine the current that the coil should carry to produce a flux of 2.5 mWb in the air-gap. Neglect magnetic leakage and fringing. The magnetization curve fore steel is given thickness of the core LABCD=LAFED= 60 cm, and the length of center cт. cast- 0.7 1.2 B (flux density) Wb / mm? 0.2 0.5 1.0 by: H (Amper-turn/ 300 540 650 900 1150 m) B 0.1 cm 60 cm 30 cm 60cm 1000 Trun 5. D

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Q1- The magnetic circuit shown is made of a cast-steel and has a coil of 1000 turns on its
center limp. The center limp and each of the side limbs has a width of 5cm and the
t =5 cm . The means length of magnetic paths
limp=30
Determine the current that the coil should carry to produce a flux of 2.5 mWb in
the air-gap. Neglect magnetic leakage and fringing. The magnetization curve fore
steel is given
thickness of the core
LABCD=LAFED=
60
cm,
and
the
length
of
center
cm.
cast-
0.7
1.2
B (flux density) Wb /
mm?
0.2
0.5
1.0
by:
(Amper-turn/ 300 540
m)
H
650 900
1150
B
0.1 cm
60 cm
30 cm
60сm
1000
Trun
5.
D
Transcribed Image Text:Q1- The magnetic circuit shown is made of a cast-steel and has a coil of 1000 turns on its center limp. The center limp and each of the side limbs has a width of 5cm and the t =5 cm . The means length of magnetic paths limp=30 Determine the current that the coil should carry to produce a flux of 2.5 mWb in the air-gap. Neglect magnetic leakage and fringing. The magnetization curve fore steel is given thickness of the core LABCD=LAFED= 60 cm, and the length of center cm. cast- 0.7 1.2 B (flux density) Wb / mm? 0.2 0.5 1.0 by: (Amper-turn/ 300 540 m) H 650 900 1150 B 0.1 cm 60 cm 30 cm 60сm 1000 Trun 5. D
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