Q1- The magnetic circuit shown is made of a cast-steel and has a coil of 1000 turns on its 5cm and the center limp. The center limp and each of the side limbs has a width of thickness of the core t =5 cm . The means length of magnetic paths limp=30 cm. Determine the current that the coil should carry to produce a flux of 2.5 mWb in the air-gap. Neglect magnetic leakage and fringing. The magnetization curve fore steel is given LABCD=LAFED= 60 cm, and the length of center cast- B (flux density) Wb/ mm? 0.2 0.5 0.7 1.0 1.2 by: (Amper-turn/ 300 540 m) H 650 900 1150 B 0.1 cm 60cm 60 cm 30 cm 5 1000 Trun 5 Is D

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Q1- The magnetic circuit shown is made of a cast-steel and has a coil of 1000 turns on its
center limp. The center limp and each of the side limbs has a width of
t =5 cm
5cm and the
thickness of the core
• The means length of magnetic paths
limp=30 cm.
Determine the current that the coil should carry to produce a flux of 2.5 mWb in
the air-gap. Neglect magnetic leakage and fringing. The magnetization curve fore
steel is given
LABCD=LAFED=
60
cm,
and
the
length
of
center
B (flux density) Wb/
mm?
cast-
0.2
0.5
0.7
1.0
1.2
by:
(Amper-turn/ 300 540
m)
H
650
900
1150
B
0.1 cm
60cm
60 cm
30 cm
5
1000
Trun
5
Is
D
Transcribed Image Text:Q1- The magnetic circuit shown is made of a cast-steel and has a coil of 1000 turns on its center limp. The center limp and each of the side limbs has a width of t =5 cm 5cm and the thickness of the core • The means length of magnetic paths limp=30 cm. Determine the current that the coil should carry to produce a flux of 2.5 mWb in the air-gap. Neglect magnetic leakage and fringing. The magnetization curve fore steel is given LABCD=LAFED= 60 cm, and the length of center B (flux density) Wb/ mm? cast- 0.2 0.5 0.7 1.0 1.2 by: (Amper-turn/ 300 540 m) H 650 900 1150 B 0.1 cm 60cm 60 cm 30 cm 5 1000 Trun 5 Is D
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