Q1: Solve the following difference equation by using Z transform (nk y(-1) = 2, y(-2) = 4 3 y(k)-y(k-1)+금y(k- 2) = 2sin( Ans: 13 112 + 85 sin Gk) - s cos (Ek): 96 y(k) =*-G) k20 Q2: The signal f (k) has Z transform as the following: 276 – 25 + 373 + 2z2 Z7 + 276 + Z5 +Z4 +0.5 F(Z) = Compute f(3). Ans: f(3) = 8 Q3: The signal f(t) = 2- 2cos(2nt) is sampled every T second. What is the Z transform for the sampled signal f(k) at T = 0. 1 sec. Q4: Find Z transform for the following sampled signal: k = 4,5, 6, . f(k) = elsewhere Q5: Write the Difference Equation for the following sampled system, and solve it: 0.2 yln) 0.4 0.4- 0.2 0.2

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Homework Q1: Solve the following difference equation by using Z transform 3 1 mk Y0 ~3y(k=1)+5y(k—2) = 2sin (T) YD =2,y(-2)=4 112 w 96 g5 Sin (Ek) e Ems(— Q2: The signal f(k) has Z transform as the following: Fy o 22437 127 D=2+ +2405 Compute f(3). Ans: f(3)=8 Q3: The signal f(t) = 2 — 2cos(2mt) is sampled every T second. What is the Z transform for the sampled signal f(k) atT = 0.1 sec. Q4: Find Z transform for the following sampled signal: (-1 k=4,56,.. fk) = 0 elsewhere Q5: Write the Difference Equation for the following sampled system, and solve it:
Homework
Q1: Solve the following difference equation by using Z transform
1
y(k) -y(k - 1) +:
y(-1) = 2, y(-2) = 4
- 2) = 2 sin
Ans:
13 1
8.
y(k) =*.
112
+
85
sin k) - 35
96
cos
k): k20
Q2: The signal f(k) has Z transform as the following:
276 – 25 + 323 + 2z2
F(Z) =
Z7 + 276 + Z5 + Z4 + 0.5
Compute f(3).
Ans: f(3) = 8
Q3: The signal f(t) = 2 - 2cos(2nt) is sampled every T second. What is the Z
transform for the sampled signal f(k) at T = 0.1 sec.
Q4: Find Z transform for the following sampled signal:
((-1)*
f(k) =
k = 4, 5, 6, ..
elsewhere
Q5: Write the Difference Equation for the following sampled system, and solve it:
x[n]
0.2
yln)
0.4
0.4
0.2
0.2
Transcribed Image Text:Homework Q1: Solve the following difference equation by using Z transform 1 y(k) -y(k - 1) +: y(-1) = 2, y(-2) = 4 - 2) = 2 sin Ans: 13 1 8. y(k) =*. 112 + 85 sin k) - 35 96 cos k): k20 Q2: The signal f(k) has Z transform as the following: 276 – 25 + 323 + 2z2 F(Z) = Z7 + 276 + Z5 + Z4 + 0.5 Compute f(3). Ans: f(3) = 8 Q3: The signal f(t) = 2 - 2cos(2nt) is sampled every T second. What is the Z transform for the sampled signal f(k) at T = 0.1 sec. Q4: Find Z transform for the following sampled signal: ((-1)* f(k) = k = 4, 5, 6, .. elsewhere Q5: Write the Difference Equation for the following sampled system, and solve it: x[n] 0.2 yln) 0.4 0.4 0.2 0.2
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