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- H.W: draw the I.L for RA, RC, RF, RD, MD, VCL, VG and MG. A 2 m B -2 m C G 0.4 m 1.6 m D 2 m- E 2 m LLS ( x³ + 4x² ) dx 1. (e –1) dx (e +1) 2.O 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading condition
- Determine the type and amount of stress in each member of the truss shown below due to wind load using the method of joints. a.) Draw FBD b.) Solve the stress of all the members c.) Tabulate your answers (Length, Force, Compression/Tension, etc.)Please, show the complete solution. Thank youDesignation Serial size 457x191 ■ Calculate the design tension resistance of the 457 × 191 × 67 UB. Given information from steel section table (assuming S275): Axis y-y cm³ 1296 67 Elastic modulus Wel Axis Z-Z cm³ 153 Mass per metre kg/m 67.1 Depth of section h mm 453.4 Width of section b mm 189.9 Plastic modulus Wpl Axis y-y cm³ 1471 Axis Z-Z cm³ 237 Thickness Thickness Root of web of flange radius tw tf mm r mm mm 8.5 12.7 Buckling parameter U 0.872 Torsional index X 37.9 10.2 Depth between fillets d mm 407.6 Ratios for local buckling Flange Web Cf/tf Cw/tw dm6 0.705 6.34 Warping Torsional constant lw constant IT cm4 37.1 48.0 Area of section cm² 85.5 Second moment of area Axis y-y cm4 29380 Axis Z-Z cm4 kNm 522 1452 Indicative values for S355 steel Mc.y.Rd Nb.z.Rd* for Lcr=3.5m kN 1600 Radius of gyration i Axis y-y cm 18.5 Axis Z-Z cm 4.12; Designation Serial size 67 457x191
- DETERMINE THE CENTROIDAL MOMENT OF INERTIA OF THE BUILT-UP SECTION SHOWN USING A STEEL PLATE 1"X16" AND C-12X25 STEEL SECTION WELDED TOGETHER. REFER TO THE TABLLE BELOW FOR THE PROPERTIES 12 Type EDSM Nomenciature AISC Manual Label C15X50 14.7 3.72 3.52 3.40 15.0 8716 0.799 404 11.0 17 C1SK40 C15X40 118 10.0 150 0520 0.400 0510 0650 0.650 0.501 0.501 0.501 0.778 348 315 C15K339 15.0 120 0.788 .07 C1200 C12X25 C12207 C1200 8.01 7.34 3.17 0.674 162 5.12 C1228 C12207 12.0 3.05 234 0.674 144 445 12.0 0.282 129 3.05 1. Determine Ixx (Centroidal) Not in the choices [Select] 1987.6 2. Determine lyy (Centroidal) 1642.67 Not in the choices 1612.7 1752.5I the Design the reinforcements of the given T beam below. bf=900mm bw=420mm tf=120mm d=550mm d'=80mm fc'=34MPA fy=415MPA USE NSCP 2015 mm2 A.Mu = 1400KN-m, As = mm2 B.Mu = 1700kN-m, As = mm2, As' = CS Scanned with CamScanner7 7a 7b 7c Alaterally supported beam was designed for flexure. The beam is safe for shear & deflection. The most economical section is structural tubing however the said section is not readily available at the time of the construction. If you are the engineer in charge of the construction what alternative section will be the best replacement? Why? The section is 8" x 8" x 7.94 mm thick: Use Fy=248 MPa: E=200,000 MPa AISC wall thickness Ix 106 S x 103 Jx 103 mm4 mm3 mm4 rx =ry Area Ag (mm2) mm Designation Weight/m 8x8 7.94 47.36 6,039 79.25 37.84 371.99 60.35 expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narative form to support your cho'ce) 8x8 14.29 80.61 10,258 76.2 59.52 585.02 99.06 8x8 72.7 9,290 76.96 54.53 539.13 90.32 8x8 9.53 56.09 7,161 78.48 44.12 432.62 70.76 mm 12.7 Zx 103 mm3 437.53 714.48 650.57 512.92
- Listen When forces are applied at more than two points along the length of a member, and when the forces are not collinear with the axis of the member, the member will be subject to bending. This is an example of a OB 3 Compression member Tension member A two-force member A multiple-force member Q Search 14 15 f6 f7 5 A 4 L FB e 19 110 % 5 € 6 & 7 8 9 0W 10x45 is connected to two plates with two lines of ¾” bolts as shown below. Determine the tensile strength of the system if Fy = 50 ksi and Fu = 65 ksi.sted ingid 250MM B k steel bar bolt AUR rigid bar 12 mm thick 8 mm Brass 350mm Jointd 16 mene thick 350mm JointB 250 mm Xg = 20x10% Eg = 90 G Pa -6 A, = 12x10/0 Es = 200 G Pa thickness> 16 mm 8 mm bolt %3D 12 mmi thick shear strength f bolf bearing streng th of holt= 100 la 50 MPa %3D Assume no failure will take place in steel or brass. Temperature chauge brass steel on Temperature change on Determine thai can be applied to system - the max