Q1: Determine the range of P for which the system of two blocks will be in equilibrium. Friction is negligible except for the surface under block B. 3007 P A 150 lb B 100 lb Hs=0.2

Q: IO JUEISUO meistos Buds e seu

A: Mass of cylinder m = 100kg Spring constant k =500N/m

Q: The tongs are used to lift the 150-kg crate, whose center of mass is at G. Suppose that 0 = 26 °.…

A: Answer The least coefficient of static friction at the pivot blocks so that the create can be lifted…

Q: Three identical 25 kg masses are stacked on top of frictionless rollers. If the system is balanced…

A:

Q: Consider (Figure 1). The cord is attached to the 39-lb block, and the coefficients of static…

A:

Q: Dětérmine the magnitude of the force P, acting as shown, that will cause the 120 N crate to move.…

A: Weight of body, coefficient of static friction is given and it has been asked to determine minimum…

Q: Question 3: Determine the required length of cord AC in figure, so that the 12 kg lamp can be…

A:

Q: Apply the principle of work and energy. When s = 0.6 m, the spring is relaxed, and the 10 kg block,…

A: Given data  Spring constant  Velocity  Distance of unstreched Spring  Force

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.