Ql: A multimode step index fiber has a numerical aperture of 0.54,core diameter of 50µm and a cladding refractive index of 1.4. TheLD at 1400nm was used as a source.Find:1. Number of the modes that are travelling in the fiber.2. Normalized frequency3. The launching angle of the third mode of propagation (assumethe reflection coefficient phase =0 degree).4. The acceptance angle of the fiber.Q2: Calculate the output optical power for 30cm polymer waveguideif the launched optical power was -3dBm. The total loss for thewaveguide was 30, 33 and 35.8dB for 10, 15 and 20cm waveguidechannels lengths, respectively.

wavelength of light=1400 nm=λ=1400×10-9 m numerical aperture, NA=0.54 Core diameter=50 μm=50×10-6…

Answered: Q1: A multimode step index fiber has a…

Similar questions

In longitudinal mechanical waves, rarefactions are the regions of . a. high particle density, low air pressure o b. high particle density, high air pressure O C. low particle density, high air pressure o d. low particle density, low air pressure Approx Light source 60° Optical Fiber The part the optical fiber represented by x is called cladding. Select one: O True False
Two sources of electromagnetic waves (light waves) are emitting coherent waves at a frequency of 546 THz. These two sources are located a distance d apart and aimed at point A, as shown below. If the top source is located a distance 3.8 meters away from point A, find the minimum distance d that will give destructive interreference. Enter your answer in millimeters. 4₁1 Laser Laser d A
Q3. Amicrowave transmitter is used to direct microwaves of wavelength 30 mm along a line XY. A metal plate is positioned at right angles to XY with its mid-point on the line, as shown. A B C X D transmitter When a detector is moved gradually along XY, its reading alternates between maxima and minima. Which one of the following statements is not correct? The distance between two minima could be 15 mm. The distance between two maxima could be 30 mm. The distance between a minimum and a maximum could be 30 mm. The distance between a minimum and a maximum could be 37.5 mm. detector metal plate Y
3. A symmetrical step index planar waveguide is shown below. Calculate the maximum acceptance angle, A, of the waveguide. (Hint: think about what could happen at the core/cladding interface) nair = 1 ANS: 15.4° ОА n₁ = 1.456 n₂ = 1.48
a. What is the angular separation between the third order fringe and the central fringe?
The wavelength limits of human vision are 400 nm to 700 nm. A. Find the minimum frequency of light that human can see underwater? The speed of light in water is 1.33 times less than in the air. B. Find the maximum frequency of light that human can see underwater? The speed of light in water is 1.33 times less than in the air. C.Find the minimum wavelenght of light that human can see underwater? The speed of light in water is 1.33 times less than in the air. D. Find the maximum wavelenght of light that human can see underwater? The speed of light in water is 1.33 times less than in the air. (Item 4)