Q.5. For the continuous beam shown in Fig., if the support B is settled by 5mm and support C settled by 2mm, by using the moment distribution method, find the following. 4.0m 2m Take (E=2*10 N/mm²) and (I= 16*10 mm) 1. Fixed end moment of AB (MFAB) is: a)-13.33 kM. m b) -19.33 kM.m c) -7.33 kM.m d) -6.33 kM.m 2. Fixed end moment of CB (MFCB) is: a) 13.6 kM. m b) 6.4 km.m c) 3.6 kM.m d) 10 kM.m 3. The modified stiffness of member CD (KcD) is equal to 3EI a) KCD = 4EI 1 b) KCD L 3EI c) KCD d) KCD 21 = ΕἸ 21 10 kN/m EI = = B 20 kN EI + 2m C FFFF 10 kN ↓ EI -3m- D
Q.5. For the continuous beam shown in Fig., if the support B is settled by 5mm and support C settled by 2mm, by using the moment distribution method, find the following. 4.0m 2m Take (E=2*10 N/mm²) and (I= 16*10 mm) 1. Fixed end moment of AB (MFAB) is: a)-13.33 kM. m b) -19.33 kM.m c) -7.33 kM.m d) -6.33 kM.m 2. Fixed end moment of CB (MFCB) is: a) 13.6 kM. m b) 6.4 km.m c) 3.6 kM.m d) 10 kM.m 3. The modified stiffness of member CD (KcD) is equal to 3EI a) KCD = 4EI 1 b) KCD L 3EI c) KCD d) KCD 21 = ΕἸ 21 10 kN/m EI = = B 20 kN EI + 2m C FFFF 10 kN ↓ EI -3m- D
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Q.S. For the continuous beam
shown in Fig., if the support B is
settled by 5mm and support C
settled by 2mm, by using the
moment distribution method,
find the following.
4.0m
-2m
Take (E=2*10 N/mm²) and (I=
16*10 mm)
1. Fixed end moment of AB (MFAB) is:
a)-13.33 km. m
b)-19.33 kM.m
c) -7.33 kM.m
d) -6.33 KM.m
2. Fixed end moment of CB (MFCB) is:
a) 13.6 km. m
b) 6.4 KM.m
c) 3.6 kM.m
d) 10 km. m
3. The modified stiffness of member CD (KCD) is equal to
3EI
a) KCD
4EI
1
b) KCD
I
3EI
c)KCD
d) KCD
=
21
21
4. For the 2nd cycle, the carry-over moment of CD is equal to
a)-0.16 kM. m
b) +0.16 kM.m
c) +0.65 kM. m
d) +0.06 kM.m
5. The final moment of member BC after 3rd cycle is:
a) +8.22 kM. m
b) -8.22 kM.m
c) +8.62 KM. m
d) -8.62 KM
Signature
Prof. Dr. Nagham Tariq ma
-
EI
10 kN/m
EI
=
B
20 KN
EL
+
2m
10 KN
↓
1m-
EI
t
3m
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98a6c7bc-18f3-46d8-94e0-ba72766c74b5%2Fc13067b7-b428-4b3e-8622-301ba4a04e60%2F0grf4yi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q.S. For the continuous beam
shown in Fig., if the support B is
settled by 5mm and support C
settled by 2mm, by using the
moment distribution method,
find the following.
4.0m
-2m
Take (E=2*10 N/mm²) and (I=
16*10 mm)
1. Fixed end moment of AB (MFAB) is:
a)-13.33 km. m
b)-19.33 kM.m
c) -7.33 kM.m
d) -6.33 KM.m
2. Fixed end moment of CB (MFCB) is:
a) 13.6 km. m
b) 6.4 KM.m
c) 3.6 kM.m
d) 10 km. m
3. The modified stiffness of member CD (KCD) is equal to
3EI
a) KCD
4EI
1
b) KCD
I
3EI
c)KCD
d) KCD
=
21
21
4. For the 2nd cycle, the carry-over moment of CD is equal to
a)-0.16 kM. m
b) +0.16 kM.m
c) +0.65 kM. m
d) +0.06 kM.m
5. The final moment of member BC after 3rd cycle is:
a) +8.22 kM. m
b) -8.22 kM.m
c) +8.62 KM. m
d) -8.62 KM
Signature
Prof. Dr. Nagham Tariq ma
-
EI
10 kN/m
EI
=
B
20 KN
EL
+
2m
10 KN
↓
1m-
EI
t
3m
D
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