Q.34: A particle of mass (m) is executing SHM about its mean position. The total energy of the particle is given instant is (CET-2006) π² mA² 2π² mА² T² T² (a) c) 4x² mA² T² (b) (d) 8π² mA² T²
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A: To find-The time (t)=?Given-T=1 sx=Asin ωt
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A: Solution:-Given thatTotal energy of the simple harmonic oscillator
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A: Detailed solution is given below:
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