Q.2) Two cylinders A and B are resting on a set of perpendicular surfaces and are held in equilibrium by a steel rod that makes angle e with the horizontal. Determine the tension in steel rod, the angle 0, and the reactions of the supporting surfaces on the cylinders. Draw the necessary free-body diagrams. WB = 200 N В WA = 800 N %3D To A Cable 60° 30°

Elements Of Electromagnetics
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### Equilibrium and Tension Analysis in a System of Two Cylinders

**Problem Statement:**

Two cylinders, A and B, are resting on a set of perpendicular surfaces and are held in equilibrium by a steel rod that makes an angle \(\theta\) with the horizontal. Given the weights of the cylinders \(W_A = 800 \, \text{N}\) for cylinder A and \(W_B = 200 \, \text{N}\) for cylinder B.

**Objective:**

1. Determine the tension in the steel rod.
2. Determine the angle \(\theta\).
3. Determine the reactions of the supporting surfaces on the cylinders.
4. Draw the necessary free-body diagrams (FBD).

**Diagram Explanation:**

- **Cylinder A** (\(W_A\)): 
  - Weight: 800 N.
  - Rests on a surface inclined at an angle of \(30^\circ\) to the horizontal.
  - Connected to a cable.

- **Cylinder B** (\(W_B\)):
  - Weight: 200 N.
  - Rests on a surface inclined at an angle of \(60^\circ\) to the horizontal.
  - Connected to the same cable.

- **Cable:**
  - Connects cylinders A and B.
  - Forms an angle \(\theta\) with the horizontal between the two cylinders.

**Solution Approach:**

1. **Free-Body Diagrams (FBD):**

   Draw the FBD of each cylinder, showing the forces acting on each, including weight (\(W_A\) and \(W_B\)), normal reaction forces from the surfaces (\(N_A\) and \(N_B\)), frictional forces if any (which may be neglected if surfaces are smooth), and the tension \(T\) in the cable.

2. **Equilibrium Equations:**

   Set up the equilibrium equations for each cylinder. For horizontal and vertical forces in both cylinders, the sum of forces must be zero.

   - For Cylinder A:
     \[
     \sum F_x = 0 \quad \text{(Horizontal forces)}
     \]
     \[
     \sum F_y = 0 \quad \text{(Vertical forces)}
     \]

   - For Cylinder B:
     \[
     \sum F_x = 0 \quad \text{(Horizontal forces)}
     \]
     \[
     \sum F_y
Transcribed Image Text:### Equilibrium and Tension Analysis in a System of Two Cylinders **Problem Statement:** Two cylinders, A and B, are resting on a set of perpendicular surfaces and are held in equilibrium by a steel rod that makes an angle \(\theta\) with the horizontal. Given the weights of the cylinders \(W_A = 800 \, \text{N}\) for cylinder A and \(W_B = 200 \, \text{N}\) for cylinder B. **Objective:** 1. Determine the tension in the steel rod. 2. Determine the angle \(\theta\). 3. Determine the reactions of the supporting surfaces on the cylinders. 4. Draw the necessary free-body diagrams (FBD). **Diagram Explanation:** - **Cylinder A** (\(W_A\)): - Weight: 800 N. - Rests on a surface inclined at an angle of \(30^\circ\) to the horizontal. - Connected to a cable. - **Cylinder B** (\(W_B\)): - Weight: 200 N. - Rests on a surface inclined at an angle of \(60^\circ\) to the horizontal. - Connected to the same cable. - **Cable:** - Connects cylinders A and B. - Forms an angle \(\theta\) with the horizontal between the two cylinders. **Solution Approach:** 1. **Free-Body Diagrams (FBD):** Draw the FBD of each cylinder, showing the forces acting on each, including weight (\(W_A\) and \(W_B\)), normal reaction forces from the surfaces (\(N_A\) and \(N_B\)), frictional forces if any (which may be neglected if surfaces are smooth), and the tension \(T\) in the cable. 2. **Equilibrium Equations:** Set up the equilibrium equations for each cylinder. For horizontal and vertical forces in both cylinders, the sum of forces must be zero. - For Cylinder A: \[ \sum F_x = 0 \quad \text{(Horizontal forces)} \] \[ \sum F_y = 0 \quad \text{(Vertical forces)} \] - For Cylinder B: \[ \sum F_x = 0 \quad \text{(Horizontal forces)} \] \[ \sum F_y
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