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How can I differentiate between internal and external forces in fbds. In problem 5.49 what is the difference between the two cases

How can I differentiate between internal and external forces in fbds. In problem 5.49 what is the difference between the two cases

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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How can I differentiate between internal and external forces in fbds. In problem 5.49 what is the difference between the two cases 

Problem 5.48 The tension in cable BC is 100 lb. Determine the reactions at the built-in support. FBD: Ay Ax Ма 200 ← Note tension is internal to this FBD. 2= 300 A B 200 lb ► 3 ft →3 ft →◄ 6 ft 6 ft 300 ft-lb Ax EFx = A₂ = 0 → Ax=0 εF₁ = Ay - 200=0 → Ay = 20016. EMA² = M₁ - 300 - 200 (3) = 0 → MA = 900 lb·ft
Transcribed Image Text:Problem 5.48 The tension in cable BC is 100 lb. Determine the reactions at the built-in support. FBD: Ay Ax Ма 200 ← Note tension is internal to this FBD. 2= 300 A B 200 lb ► 3 ft →3 ft →◄ 6 ft 6 ft 300 ft-lb Ax EFx = A₂ = 0 → Ax=0 εF₁ = Ay - 200=0 → Ay = 20016. EMA² = M₁ - 300 - 200 (3) = 0 → MA = 900 lb·ft
Problem 5.49 The tension in cable AB is 2 kN. What are the reactions at C in the two cases? * Assume all components are weight less. a) FBD: T {√₁₂₁²= = =²/²₂T+C₁₂₁₂=0 Cx ==T=IKN ≤E₁₂x = C²₂₂=0 EFy = C₁ = 0 Cy A 'Cy 60° B C Mc Jocx -2 m Me (a) 1 m 2 EM₂²² = M₁ = 0 Cx A 60° BC - 2 m ✦1m EM ₂²/² = M₁₂ - T (3) - VT (1) =0 → Mc = 7₁, 73 kN.m b) FBD: tension is internal to this FBD (b) EFy=C₂₂+T+₂ ²/² T = 0 C₁ = -3.73 KN the be 4 Popular ww
Transcribed Image Text:Problem 5.49 The tension in cable AB is 2 kN. What are the reactions at C in the two cases? * Assume all components are weight less. a) FBD: T {√₁₂₁²= = =²/²₂T+C₁₂₁₂=0 Cx ==T=IKN ≤E₁₂x = C²₂₂=0 EFy = C₁ = 0 Cy A 'Cy 60° B C Mc Jocx -2 m Me (a) 1 m 2 EM₂²² = M₁ = 0 Cx A 60° BC - 2 m ✦1m EM ₂²/² = M₁₂ - T (3) - VT (1) =0 → Mc = 7₁, 73 kN.m b) FBD: tension is internal to this FBD (b) EFy=C₂₂+T+₂ ²/² T = 0 C₁ = -3.73 KN the be 4 Popular ww
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