Q.2 The heat absorption and rejection temperatures of a Carnot refrigeration cycle are -8°C and 55°C respectively. The heat rejection rate is 30 kW. There is a temperature difference of 6°C between the refrigerant and two heat reservoirs. The internal processes of the cycle are reversible. (a) Calculate the work input, and the COP of the refrigeration cycle. (b) If the cycle is operated as a heat pump, calculate heat absorption rate and the COP. [Answers: (a) 6.74 kW. 3.45. (b) 23.26 kW. 4.451

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Q.2
refrigeration cycle are -8°C and 55°C respectively. The heat rejection
rate is 30 kW. There is a temperature difference of 6°C between the
refrigerant and two heat reservoirs. The internal proccsses of the cycle
are reversible. (a) Calculate the work input, and the COP of the
refrigeration cycle. (b) If the cycle is operated as a heat pump, calculate
heat absorption rate and the COP.
[Answers: (a) 6.74 kW, 3.45, (b) 23.26 kW, 4.45]
The heat absorption and rejection tempcraturcs of a Carnot
Transcribed Image Text:Q.2 refrigeration cycle are -8°C and 55°C respectively. The heat rejection rate is 30 kW. There is a temperature difference of 6°C between the refrigerant and two heat reservoirs. The internal proccsses of the cycle are reversible. (a) Calculate the work input, and the COP of the refrigeration cycle. (b) If the cycle is operated as a heat pump, calculate heat absorption rate and the COP. [Answers: (a) 6.74 kW, 3.45, (b) 23.26 kW, 4.45] The heat absorption and rejection tempcraturcs of a Carnot
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