Q.2: A 5 mA diode is connected in series with a 100 ohms resistance and a DC voltage source derived from the output of a half-wave rectifier (HWR). The ac voltage driving the rectifier is of amplitude 35 volts. (a) What will be the DC current through the diode (use exponential l-V relation for the diode, and iteration method)? (b) What will be the ac resistance of the diode?
Q.2: A 5 mA diode is connected in series with a 100 ohms resistance and a DC voltage source derived from the output of a half-wave rectifier (HWR). The ac voltage driving the rectifier is of amplitude 35 volts. (a) What will be the DC current through the diode (use exponential l-V relation for the diode, and iteration method)? (b) What will be the ac resistance of the diode?
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![Q.2: A 5 mA diode is connected in series with a 100 ohms resistance and a DC voltage source derived
from the output of a half-wave rectifier (HWR). The ac voltage driving the rectifier is of amplitude 35
volts.
(a) What will be the DC current through the diode (use exponential l-V relation for the diode, and
iteration method)?
(b) What will be the ac resistance of the diode?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F151580ce-93df-4355-9aa2-20849d44482a%2F382c2e40-76ba-4088-b209-99a32595686e%2Fpjpmvgd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q.2: A 5 mA diode is connected in series with a 100 ohms resistance and a DC voltage source derived
from the output of a half-wave rectifier (HWR). The ac voltage driving the rectifier is of amplitude 35
volts.
(a) What will be the DC current through the diode (use exponential l-V relation for the diode, and
iteration method)?
(b) What will be the ac resistance of the diode?
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