Q.19 450 Kg//hr of steam at 40 bar and 450°C (V = 80 liter/Kg) enters a turbine at a velocity of 50 m/sec. The outlet steam leaves the turbine at a point of 5.1 m below the inlet point at 1 bar and 140°C (V = 1900 liter/Kg) with a velocity of 300 m/sec. The turbine produces shaft work at a rate of 65 KW. The heat is lost from the turbine at a rate of 40000 Btu/hr. Calculate the specific changes in enthalpy and internal energy (AH and AU ) in KJ/Kg associated with such process. Given that: 1 Btu = 252 Cal, 1Cal = 4.184 J, 1KJ = 10 liter.bar, 1bar 100 Kpa
Q.19 450 Kg//hr of steam at 40 bar and 450°C (V = 80 liter/Kg) enters a turbine at a velocity of 50 m/sec. The outlet steam leaves the turbine at a point of 5.1 m below the inlet point at 1 bar and 140°C (V = 1900 liter/Kg) with a velocity of 300 m/sec. The turbine produces shaft work at a rate of 65 KW. The heat is lost from the turbine at a rate of 40000 Btu/hr. Calculate the specific changes in enthalpy and internal energy (AH and AU ) in KJ/Kg associated with such process. Given that: 1 Btu = 252 Cal, 1Cal = 4.184 J, 1KJ = 10 liter.bar, 1bar 100 Kpa
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Q.19 450 Kg/hr of steam at 40 bar and 450°C (V = 80 liter/Kg) enters a turbine at a
velocity of 50 m/sec. The outlet steam leaves the turbine at a point of 5.1 m below the inlet
point at 1 bar and 140°C (V =1900 liter/Kg) with a velocity of 300 m/sec. The turbine
produces shaft work at a rate of 65 KW. The heat is lost from the turbine at a rate of 40000
Btu/hr. Calculate the specific changes in enthalpy and internal energy (AH and AU ) in
KJ/Kg associated with such process. Given that: 1 Btu = 252 Cal, 1Cal = 4.184 J,
1KJ = 10 liter.bar, 1bar = 100 Kpa
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