Q. Write a single 8086 assembly instruction to execute the following: 1. Toggle the logic level of even bits in the Accumulator Register. 2. Swap the [(DS)0+(BX)+(DI)+3FFFH]. contents of DX with the contents of memory location 3. Find the squares of BL and save the result in AX, when (AL)=(BL). 4. Subtract the word content of the storage location pointed by base-indexed addressing mode [BX]+[SI] from the register AX. 5. Call a far-process subroutine, if the physical address of the subroutine is 11002h in CS=1100h. 6. Divide the signed number in register DX by 16, when CL=4. 7. Save the status flags in stack memory. 8. Load the BX and ES registers from the address [AB00H] and address [AB02H] respectively. 9. Move the content of the low nibble of AH to high nibble and clear the low nibble, when CL=4. 10. Jump to code memory location LABEL when the (CX) #0 or (ZF)=1.
Q. Write a single 8086 assembly instruction to execute the following: 1. Toggle the logic level of even bits in the Accumulator Register. 2. Swap the [(DS)0+(BX)+(DI)+3FFFH]. contents of DX with the contents of memory location 3. Find the squares of BL and save the result in AX, when (AL)=(BL). 4. Subtract the word content of the storage location pointed by base-indexed addressing mode [BX]+[SI] from the register AX. 5. Call a far-process subroutine, if the physical address of the subroutine is 11002h in CS=1100h. 6. Divide the signed number in register DX by 16, when CL=4. 7. Save the status flags in stack memory. 8. Load the BX and ES registers from the address [AB00H] and address [AB02H] respectively. 9. Move the content of the low nibble of AH to high nibble and clear the low nibble, when CL=4. 10. Jump to code memory location LABEL when the (CX) #0 or (ZF)=1.
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![Q. Write a single 8086 assembly instruction to execute the following:
1. Toggle the logic level of even bits in the Accumulator Register.
2. Swap the
[(DS)0+(BX)+(DI)+3FFFH].
contents
of DX
with
the
contents
of
memory
location
3. Find the squares of BL and save the result in AX, when (AL)=(BL).
4. Subtract the word content of the storage location pointed by base-indexed addressing
mode [BX]+[SI] from the register AX.
5. Call a far-process subroutine, if the physical address of the subroutine is 11002h in
CS=1100h.
6. Divide the signed number in register DX by 16, when CL=4.
7. Save the status flags in stack memory.
8. Load the BX and ES registers from the address [AB00H] and address [AB02H]
respectively.
9. Move the content of the low nibble of AH to high nibble and clear the low nibble,
when CL=4.
10. Jump to code memory location LABEL when the (CX) #0 or (ZF)=1.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F808b3308-7a05-4d3d-b583-ec8136c55e9f%2F25d285b0-2b88-4c10-b2a6-4035902c7594%2Fx99554s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q. Write a single 8086 assembly instruction to execute the following:
1. Toggle the logic level of even bits in the Accumulator Register.
2. Swap the
[(DS)0+(BX)+(DI)+3FFFH].
contents
of DX
with
the
contents
of
memory
location
3. Find the squares of BL and save the result in AX, when (AL)=(BL).
4. Subtract the word content of the storage location pointed by base-indexed addressing
mode [BX]+[SI] from the register AX.
5. Call a far-process subroutine, if the physical address of the subroutine is 11002h in
CS=1100h.
6. Divide the signed number in register DX by 16, when CL=4.
7. Save the status flags in stack memory.
8. Load the BX and ES registers from the address [AB00H] and address [AB02H]
respectively.
9. Move the content of the low nibble of AH to high nibble and clear the low nibble,
when CL=4.
10. Jump to code memory location LABEL when the (CX) #0 or (ZF)=1.
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