Q. A straight, horizontal stretch of copper wire has a current i= 28 A through it. What are the magnitude and direction of the minimum magnetic field needed to suspend the wire, i. e. to balance its weight? Its linear density is 46.6 g/m. Ans. 1.6 x 10-2 T FB mg

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Chapter1: Units, Trigonometry. And Vectors
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**Q.** A straight, horizontal stretch of copper wire has a current \(i = 28 \, \text{A}\) through it. What are the magnitude and direction of the minimum magnetic field needed to suspend the wire, i.e., to balance its weight? Its linear density is \(46.6 \, \text{g/m}\).

**Ans.** \(1.6 \times 10^{-2} \, \text{T}\)

**Diagram Explanation:**

- The diagram shows a wire with three forces acting on it:
  - \(F_B\) (magnetic force) is directed upwards.
  - \(mg\) (gravitational force or weight of the wire) is directed downwards.
  - \(B\) (magnetic field) is directed horizontally to the right.

The perpendicular arrangement of the magnetic field and the current in the wire results in the magnetic force (\(F_B\)) that acts upwards to balance the gravitational force, allowing the wire to be suspended.
Transcribed Image Text:**Examples** **Q.** A straight, horizontal stretch of copper wire has a current \(i = 28 \, \text{A}\) through it. What are the magnitude and direction of the minimum magnetic field needed to suspend the wire, i.e., to balance its weight? Its linear density is \(46.6 \, \text{g/m}\). **Ans.** \(1.6 \times 10^{-2} \, \text{T}\) **Diagram Explanation:** - The diagram shows a wire with three forces acting on it: - \(F_B\) (magnetic force) is directed upwards. - \(mg\) (gravitational force or weight of the wire) is directed downwards. - \(B\) (magnetic field) is directed horizontally to the right. The perpendicular arrangement of the magnetic field and the current in the wire results in the magnetic force (\(F_B\)) that acts upwards to balance the gravitational force, allowing the wire to be suspended.
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