**Q.2) Using the Method of Joints:** **a) Find the force in members GJ, JD, JC, and GC.** **b) State whether each member is in tension or compression.**---**Diagram Description:**The diagram provided is a truss structure with different members and external forces applied. Below is a detailed explanation of the truss layout:- The truss rests on supports at points A and E.- Horizontal distances between the joints are labeled: 3 meters between A and B, 3 meters between B and C, 3 meters between C and D, and 3 meters between D and E.- The vertical height from the base (A through E) to point G is labeled as 4 meters.**External Forces Applied:**- A downward force of 6 kN is applied at joint A.- A downward force of 4 kN is applied at joint H.- A downward force of 10 kN is applied at joint G.- A downward force of 8 kN is applied at joint J.- A downward force of 5 kN is applied at joint E.**Joints and Members:**- The truss consists of several joints connected by straight members.- Joint G is the top of the truss, and it forms a triangle with joints H (left) and J (right).- There are multiple members connecting the various joints: - AB, BH, HC, and CE are horizontal members. - AG, GH, GJ, and JE are inclined members. - Vertical members: HJ and GC.---To solve for the forces in members GJ, JD, JC, and GC:1. **Joint G**: - Consider equilibrium conditions (ΣF_x = 0, ΣF_y = 0) to solve for forces in members connected to G. - Given the load, calculate the reaction forces at the supports (A and E).2. **Member Forces**: - Use trigonometry for inclined members to determine the horizontal and vertical components. - Determine if each member is in tension (pulling apart) or compression (pushing together).Let's apply these principles step-by-step to find the forces in the specific members GJ, JD, JC, and GC, determining if they are in tension or compression accordingly. Complete calculations require equilibrium equations and methodical resolution for

Given truss members and asked to determine the force in members GJ, JD, JC and GC and also to…

Q. 2) Using the Method of Joints: a) Find the force in members GJ, JD, JC, and GC. b) State whether each member is in tension or compression. 10 kN 6 KN A go 000 3 m 4 kN B H 3 m 4 m 3 m 8 kN D 2 m 3 m 5 kN E

Q. 2) Using the Method of Joints: a) Find the force in members GJ, JD, JC, and GC. b) State whether each member is in tension or compression. 10 kN 6 KN A go 000 3 m 4 kN B H 3 m 4 m 3 m 8 kN D 2 m 3 m 5 kN E

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter4: Plane And Space Trusses

Section: Chapter Questions

Problem 53P

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Concept explainers

Load on Structures

Civil engineers primarily deal with beams in their day-to-day applications. A beam is a structural member that resists shear loadings. There are various types of beams such as cantilever beam, simply supported beam, and over the hanging beam. All these beams have a different end and loading conditions.

Question

**Q.2) Using the Method of Joints:**

**a) Find the force in members GJ, JD, JC, and GC.**

**b) State whether each member is in tension or compression.**

---

**Diagram Description:**
The diagram provided is a truss structure with different members and external forces applied. Below is a detailed explanation of the truss layout:

- The truss rests on supports at points A and E.
- Horizontal distances between the joints are labeled: 3 meters between A and B, 3 meters between B and C, 3 meters between C and D, and 3 meters between D and E.
- The vertical height from the base (A through E) to point G is labeled as 4 meters.

**External Forces Applied:**
- A downward force of 6 kN is applied at joint A.
- A downward force of 4 kN is applied at joint H.
- A downward force of 10 kN is applied at joint G.
- A downward force of 8 kN is applied at joint J.
- A downward force of 5 kN is applied at joint E.

**Joints and Members:**
- The truss consists of several joints connected by straight members.
- Joint G is the top of the truss, and it forms a triangle with joints H (left) and J (right).
- There are multiple members connecting the various joints:
- AB, BH, HC, and CE are horizontal members.
- AG, GH, GJ, and JE are inclined members.
- Vertical members: HJ and GC.

---

To solve for the forces in members GJ, JD, JC, and GC:

1. **Joint G**:
- Consider equilibrium conditions (ΣF_x = 0, ΣF_y = 0) to solve for forces in members connected to G.
- Given the load, calculate the reaction forces at the supports (A and E).

2. **Member Forces**:
- Use trigonometry for inclined members to determine the horizontal and vertical components.
- Determine if each member is in tension (pulling apart) or compression (pushing together).

Let's apply these principles step-by-step to find the forces in the specific members GJ, JD, JC, and GC, determining if they are in tension or compression accordingly. Complete calculations require equilibrium equations and methodical resolution for

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