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- 2. A child running around in a field has the following position and velocity at time t = 0: x = 1.5 m, y = 2.0 m Vx = -3.5 m/s, vy=-1.0 m/s At time t = 2.5 s, it has the following position and velocity: x = -2.0 m, y = 1.5 m vx = -0.50 m/s, v, = 2.0 m/s Using this information, find the child's average velocity and average acceleration during that time interval. Write your answers in unit vector notation.The position of a particle moving a long x-axis is given by x (t) =8 t2-2t°, where x in meter and t in is in seconds. Find the acceleration at t = 3.0 s. Select one: OA. 6.0 m/s? B. 20.0 m/s2 C. -42.0 m/s2 D. -6.0 m/s? E. -20.0 m/s2 Previous page Next page - Torque and Equilibrium Jump to... Chapter-9-Equilibrium of rigid bodiesA ball rolls down from the top of an inclined plane. The displacements for the first 3 seconds are 2.40 m, 9.84 m, and 22.00 m. a. What is the average velocity of the ball at the end of 1s? 2s? 3s? b. What is the average acceleration of the ball at the end of 1s? 2s? 3s? c. What is the average of the accelerations obtained in (b)?
- A train traveling due to East (+x-axis) with a velocity of v=30 m/s stops with a uniform acceleration in At=60s. What is the acceleration (a) of the train? a. + 5i m/s? O b. -0.5 i m/s² С. +155 i m/s?A particle is moving with a motion defined by x = 6t + 2t m, what is the equation for the acceleration? A. a =0 B. a = 36t m/s? = 3t/10 + t/3 m/s? D. a = 18t? +2 m/s E. None of the above. C. aPlease add the solution to the problem.Q16
- A cyclist rides down a long straight road at a velocity (in m/min) given by v(t) = 400 - 20t, for 0≤t≤ 10. a. How far does the cyclist travel in the first 3 min? b. How far does the cyclist travel in the first 10 min? c. How far has the cyclist traveled when his velocity is 350 m/min?4. A robotic vehicle is exploring the surface of Mars. The robot, which is represented as a point, has x - and y-coordinates that vary with time: x = (3 − 2t); y = (-t² + 4t³) where x and y are in meters and t is in seconds. a. Find the average velocity of the robot between t = 0s and t = 2s. b. Find the average acceleration of the robot between t = 0s and t = 2s. c. At what time the acceleration of the robot will be zero. a. Vavg= -21 + 14ĵ m/s b. davg = 22ĵ C. m s² 2 t = = = 0.083 s 24A ball is thrown straight up. What is the velocity and acceleration of the ball at the higest point (peak)? A. velocity = 0m/s and acceration = 9.8 m/s2 down. B. velocity = 0 m/s amd acceleration = 0 m/s2 C. velocity = 0 m/s and acceleration = 9.8 m/s2 up D. velocity = 9.8 m/s up and acceleration = 0 m/s2
- 1. The acceleration of a car is given by a(t) = A – Bt + Ct² , where A = 1.0 m/s², B = 0.5 m/s³, C = 2.0 m/s“. The car is at rest at the origin at time t= 0. Find its position and velocity as a function of time. b. Sketch its position, velocity, and acceleration. a.A particle travels along the +x axis. At t = 0 s, its velocity is 10.0 m/s and its acceleration is -2.0 m/s^2. Question A: Which of the following statements is true? 1. The particle will slow down and eventually come to a complete stop 2. The particle cannot have a negative acceleration and be moving in the positive x direction 3. The particle will continue to move in the positive x direction, slowing but never coming to a complete stop. 4. The particle will slow down, stop momentarily, then speed up in the x- direction. Question B: At what time will the particle be stopped? 1. t = 5.0 s 2. t = -5.0 s 3. t = -0.2 s 4. The particle does not ever stop Question C: What is the particle's displacement from its initial position at t = 10.0 s ? Please Answer questions A, B, and Ca. Find the velocity v(t) and acceleration a(t). b. At what value of t does v=0? c. What is the maximum height?