Q 4. Three equal charges are placed at the vertices of an equilateral triangle of side L. What is the magnitude and direction of the Coulomb force on the charge q at the point A? (q=10µC and a=V4). A B C
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![Q 4.
Three equal charges are placed at the vertices of an equilateral triangle of side L.
What is the magnitude and direction of the Coulomb force on the charge q at the point A?
(q=10µC and a=V4).
A
C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F825d9971-0c81-477c-b648-6fea09a31d20%2F189d76db-5076-46b0-91ce-8ccb59e36c5e%2Fqyyln3t_processed.png&w=3840&q=75)
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- Two stationary positive point charges, charge 1 of magnitude 3.30 nC and charge 2 of magnitude 1.90 nC, are separated by a distance of 44.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed Ufinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second. ▸ View Available Hint(s) ΨΕ ΑΣΦ Ufinal=5.44.106 Submit Previous Answers * Incorrect; Try Again; 3 attempts remaining m/sA charged ring with charge Q = 644 nC and radius R=0.67 m is placed in a tank of water. What is the electric field at the point z = 0.085 m above the midpoint of the ring, if the dielectric constant of water is 80.4? Answer in N/C and round your answer to have one digit after the decimal. Water 20 °C K = 80.4 Your Answer: AnswerCalculate the magnitude and direction of the Coulomb force on each of the three charges shown in the figure below. 6.00 μC charge: magnitude direction 89.855 X Your response differs from the correct answer by more than 10%. Double check your calculations. N toward the left V 1.50 μC charge: magnitude direction 29.9585 X Your response differs from the correct answer by more than 10%. Double check your calculations. N toward the right v -2.00 μC charge: magnitude direction -29.9585 X The response you submitted has the wrong sign. N toward the left V 6.00 μC + 1.50 μC -2.00 μC 3.00 cm -2.00 cm →
- a.) two balloons (m = 0.023 kg) are separated by a distance of d = 14m. they are released from rest and observed to have an acceleration of a = 1.5 m/s2 toward each other at the moment they are released. assume the two balloons are point charges and have equal byt opposite reactions b.) how many electrons are responsible for the charge, n?"Two particle with charges Q and -Q are fixed at the vertices of an equilateral triangle with sides of length A). If k = 4TEO, the work required to move a particle with charge q from the other vertex to the center of the line joining the fixed %3D a particles is :Select one kQq/av2 a kQq/a2 b kQq/a c 2kQq/a .dThree point charges are arranged as shown in the figure below. 5.00 nC -3.00 nC 0.300 m 0.100 m Ⓡ (a) Find the vector electric field that the q = 6.50 nC and -3.00 nC charges together create at the origin. X Your response differs from the correct answer by more than 10%. Double check your calculations. N/C Î + (b) Find the vector force on the 5.00 nC charge. UN Î+ UN Ĵ N/Cĵ
- 5. Consider four identical charged particles carrying a total charge 8 µC. The three particles are arranged in a square of side length 5 cm. Imagine that the square symmetrically surrounds the x-axis, so that the r-axis passes straight through the midpoint of the square. What is the total voltage at a point on the r-axis a distance of 12 cm away from the midpoint of the square? SpCo_5cm 8pC x-awis pasing thircugh 5cm 5cm VLotal Submit All Answers = %3D 8uC 5cm YpCTwo stationary, positive, point charges that are originally separated by a distance of 6.00 cm experience a mutually repulsive force of magnitude 8.00 μN. What will be the magnitude of the repulsive force between the two charges when their distance of separation is reduced to 1.50 cm? a. 128 μN b. 32.0 μN c. 96.0 μN d. 160 μN e. 64.0 μN4
- 26 bTwo identical balls of 29.5 g are suspended from threads of length 1.1 m and carry equal charges as shown in the figure. Each ball is 1.5 cm from the centerline.a) Assume that the angle Θ is so small that its tangent can be replaced by its sine. This is called the small angle approximation and means that for small angles sin(Θ)=tan(Θ). Find the magnitude of charge on one of the balls. b) Now, assume the two balls are losing charge to the air very slowly. That means they'll be slowly approaching each other. If a ball is moving at an instantaneous speed of 2.50E−05 m/s, at what rate is the ball losing charge? Start by writing the speed of the ball and the rate of change of the charge as symbolic derivatives, and then relate those derivatives. Give your answer in Coulombs per second (C/s). Note that because the balls are losing charge so slowly, we can still use our results from the previous part, as the system is almost in equilibrium. Give your answer as a magnitude.As shown below, an alpha particle (m = 6.642 × 10-27 kg, q = +2e) is shot upward with an initial speed of v; = 3.50 x 105 m/s from one large plate of charge toward another large plate of 8. charge. Each plate has a charge density given below. Assume gravity is negligible. а. Find the speed of the alpha particle once it hits the positively charged plate. b. Which plate is at the higher potential, the top plate or the bottom plate? Explain using physical reasonng. 02 = +2.50 µC/m² 2.00 mm V; = 3.50 × 10° m/s 01 = +4.50 µC/m²