As shown below, an alpha particle (m = 6.642 × 10-27 kg, q = +2e) is shot upward with an initial speed of v; = 3.50 x 105 m/s from one large plate of charge toward another large plate of 8. charge. Each plate has a charge density given below. Assume gravity is negligible. а. Find the speed of the alpha particle once it hits the positively charged plate. b. Which plate is at the higher potential, the top plate or the bottom plate? Explain using physical reasonng. っ= +2.50 μC/m? 2.00 mm V; = 3.50 × 10° m/s 01 = +4.50 µC/m²
As shown below, an alpha particle (m = 6.642 × 10-27 kg, q = +2e) is shot upward with an initial speed of v; = 3.50 x 105 m/s from one large plate of charge toward another large plate of 8. charge. Each plate has a charge density given below. Assume gravity is negligible. а. Find the speed of the alpha particle once it hits the positively charged plate. b. Which plate is at the higher potential, the top plate or the bottom plate? Explain using physical reasonng. っ= +2.50 μC/m? 2.00 mm V; = 3.50 × 10° m/s 01 = +4.50 µC/m²
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
Transcribed Image Text:As shown below, an alpha particle (m = 6.642 × 10-27 kg, q = +2e) is shot upward with an
initial speed of v; = 3.50 x 105 m/s from one large plate of charge toward another large plate of
8.
charge. Each plate has a charge density given below. Assume gravity is negligible.
а.
Find the speed of the alpha particle once it hits the positively charged plate.
b.
Which plate is at the higher potential, the top plate or the bottom plate? Explain
using physical reasonng.
02 = +2.50 µC/m²
2.00 mm
V; = 3.50 × 10° m/s
01 = +4.50 µC/m²
Expert Solution
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Step 1
Part a:
The work done by the electric field between the plates on the particle is converted to its kinetic energy.
Substitute the required values and solve.
Step by step
Solved in 2 steps with 2 images
