Q 3. Find self inductance for coil shown belowConsider N=40 0Permeebility M= a lodis Ampe8 mml=1ocm

It is given that: N=400i=15 Al=10 cm=10×10-2=0.1 mRadius=r=8 mm=8×10-3m=0.008 mμ=2μo

Answered: Q 3. Find self inductance for coil…

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Q 3. Find self inductance for coil shown below Considee N=400 Permeebity u= a lo 15 Ampe 8 mm l=1ocm

Introductory Circuit Analysis (13th Edition)

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ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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Capacitor

The capacitor is an element used to store electrical energy in the electrical field. A capacitor is a form of passive energy.

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Q 3. Find self inductance for coil shown below
Consider N=40 0
Permeebility M= a lo
dis Ampe
8 mm
l=1ocm

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