Q-3 Consider a large parallel plate capacitor. The gap d between the two plates is filled entirely with a dielectric slab of relative permittivity The plates are initially charged to a potential difference of V volts and then disconnected from the source. If the dielectric slab is pulled out completely, then the ratio of the new electric field E2 in the gap to the original electric field E1 is
Q-3 Consider a large parallel plate capacitor. The gap d between the two plates is filled entirely with a dielectric slab of relative permittivity The plates are initially charged to a potential difference of V volts and then disconnected from the source. If the dielectric slab is pulled out completely, then the ratio of the new electric field E2 in the gap to the original electric field E1 is
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter19: Capacitors
Section: Chapter Questions
Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...
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Find required ratio,
![Q-3 Consider a large parallel plate capacitor. The gap d between the two plates is filled entirely with a
dielectric slab of relative permittivity The plates are initially charged to a potential difference of V volts
and then disconnected from the source. If the dielectric slab is pulled out completely, then the ratio of
the new electric field E2 in the gap to the original electric field E1 is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fde1477f8-c972-49f7-835e-5a609bc70bcf%2Fc6eb95e1-5610-4117-a2fe-f05084b80d32%2F5z77n9b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q-3 Consider a large parallel plate capacitor. The gap d between the two plates is filled entirely with a
dielectric slab of relative permittivity The plates are initially charged to a potential difference of V volts
and then disconnected from the source. If the dielectric slab is pulled out completely, then the ratio of
the new electric field E2 in the gap to the original electric field E1 is
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