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Q-3 A) If tension surface of the globule in transformer oil is 0.15N/m, radius of globule is
2µm, the relative permittivity of the oil is 4.5 and of the globule is 9 find the critical
electrical field.

Expert Solution

Step 1

Given :

Surface tension = 0.15N/m

Radius of globule (R) = 2 $μ m$ = $10^{- 6}$ $2 \times 10^{- 6}$ m

$Relative permitivity of oil (ξ) = 4.5 Relative permitiivty of globule (ξ_{2}) = 9$

$Relative permitivity of oil (ξ) = 4.5 Relative permitiivty of globule (ξ_{2}) = 9$

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