(python)Find at least 12 issues in the code.A = int(input("Enter a number for A: "))B = str(input("Enter a number for B: "))C = int(input("Enter a number for C: "))#Check that user input for A is not 0.if A = 0: print("Your coefficient for 'A' MUST BE a value greater than 0, otherwise your equation is not a quadratic!") int(input(Please enter a new value for a:")) = Aimport math://Compute the discriminant.disc = (B*B) - (4*A*C)#Display the disciminant computed.print("\nThe discriminant of your equation is", str(disc) + ".")#Check the sign of the computed discriminantif disc == 0: print("This equation has 1 real solution.") x = (-B + math.sqrt(disc)) / (2 * A) print("The solution to your equation is:", x)elif disc > 0 print("This equation has 2 real solutions.") x1 == (-B + math.sqrt(disc)) / (2 * A) x2 == (-B - math.sqrt(disc)) / (2 * A) print("One solution to your equation is:", x1) print("The other solution to your equation is:" + x2)else if disc < 0: print "This equation has 2 imaginary solutions.")

A = int(input("Enter a number for A: ")) B = str(input("Enter a number for B: ")) C =…

Answered: python) Find at least 12 issues in the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Question

(python)

Find at least 12 issues in the code.

A = int(input("Enter a number for A: "))
B = str(input("Enter a number for B: "))
C = int(input("Enter a number for C: "))
#Check that user input for A is not 0.
if A = 0:
print("Your coefficient for 'A' MUST BE a value greater than 0, otherwise your equation is not a quadratic!")
int(input(Please enter a new value for a:")) = A
import math:
//Compute the discriminant.
disc = (B*B) - (4*A*C)
#Display the disciminant computed.
print("\nThe discriminant of your equation is", str(disc) + ".")
#Check the sign of the computed discriminant
if disc == 0:
print("This equation has 1 real solution.")
x = (-B + math.sqrt(disc)) / (2 * A)
print("The solution to your equation is:", x)
elif disc > 0
print("This equation has 2 real solutions.")
x1 == (-B + math.sqrt(disc)) / (2 * A)
x2 == (-B - math.sqrt(disc)) / (2 * A)
print("One solution to your equation is:", x1)
print("The other solution to your equation is:" + x2)
else if disc < 0:
print "This equation has 2 imaginary solutions.")

Expert Solution

Step 1

1. A = int(input("Enter a number for A: "))
2. B = str(input("Enter a number for B: "))
3. C = int(input("Enter a number for C: "))
4. #Check that user input for A is not 0.
5. if A = 0:
6. print("Your coefficient for 'A' MUST BE a value greater than 0, otherwise your equation is not a quadratic!")
7. int(input(Please enter a new value for a:")) = A
8. import math:
9. //Compute the discriminant.
10. disc = (B*B) - (4*A*C)
11. #Display the disciminant computed.
12. print("\nThe discriminant of your equation is", str(disc) + ".")
13. #Check the sign of the computed discriminant
14. if disc == 0:
15. print("This equation has 1 real solution.")
16. x = (-B + math.sqrt(disc)) / (2 * A)
17. print("The solution to your equation is:", x)
18. elif disc > 0
19. print("This equation has 2 real solutions.")
20. x1 == (-B + math.sqrt(disc)) / (2 * A)
21. x2 == (-B - math.sqrt(disc)) / (2 * A)
22. print("One solution to your equation is:", x1)
23. print("The other solution to your equation is:" + x2)
24. else if disc < 0:
25. print "This equation has 2 imaginary solutions.")
all the bold sentence in program has error

Correct program

A = int(input("Enter a number for A: "))
B = int(input("Enter a number for B: "))
C = int(input("Enter a number for C: "))
if A == 0:
print("Your coefficient for 'A' MUST BE a value greater than 0, otherwise your equation is not a quadratic!")
A=int(input("Please enter a new value for a:"))
import math
#Compute the discriminant.
disc = (B*B) - (4*A*C)
#Display the disciminant computed.
print("\nThe discriminant of your equation is", str(disc) + ".")
#Check the sign of the computed discriminant
if disc == 0:
print("This equation has 1 real solution.")
x = (-B + math.sqrt(disc)) / (2 * A)
print("The solution to your equation is:", x)
elif disc > 0:
print("This equation has 2 real solutions.")
x1 == (-B + math.sqrt(disc)) / (2 * A)
x2 == (-B - math.sqrt(disc)) / (2 * A)
print("One solution to your equation is:", x1)
print("The other solution to your equation is:" + x2)
elif disc < 0:
print ("This equation has 2 imaginary solutions.")

output

Enter a number for A: 2
Enter a number for B: 3
Enter a number for C: 4
The discriminant of your equation is -23.
This equation has 2 imaginary solutions.

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here