checks whether the point is within the circle centered at (0, 0) with radius 10. For example, (4, 5) is inside the circle and (9, 9) is outside the circle, as shown in Figure below y-axis (9,9) (4,5) & (0,0) x-axis Hint: A point is in the circle if its distance to (0, 0) is less than or equal to 10. The formula for computing the distance between two points is given by √(22 − 21 )² + (32 − 3/1 )² Test your program to test all cases. Two sample runs are shown here. Enter a point with two coordinates: 4 5 Point (4, 5) is in the circle Enter a point with two coordinates: 99 Point (9, 9) is not in the circle Enter Enter

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Please review the image below. Produce the program in C++. Upload screenshots of Code and Output, as well as the source code.

7

7. (Geometry: point in a circle?) Write a program that prompts the user to enter a point (x, y) and
checks whether the point is within the circle centered at (0, 0) with radius 10. For example, (4, 5)
is inside the circle and (9, 9) is outside the circle, as shown in Figure below
y-axis
(4,5)
(0,0)
(9,9)
x-axis
Hint: A point is in the circle if its distance to (0, 0) is less than or equal to 10. The formula for
computing the distance between two points is given by
√(x2 − 1)² + (32 − Y₁ )²
Test your program to test all cases. Two sample runs are shown here.
Enter a point with two coordinates: 4 5 Enter
Point (4, 5) is in the circle
Enter a point with two coordinates: 99
Point (9, 9) is not in the circle
Enter
Transcribed Image Text:7. (Geometry: point in a circle?) Write a program that prompts the user to enter a point (x, y) and checks whether the point is within the circle centered at (0, 0) with radius 10. For example, (4, 5) is inside the circle and (9, 9) is outside the circle, as shown in Figure below y-axis (4,5) (0,0) (9,9) x-axis Hint: A point is in the circle if its distance to (0, 0) is less than or equal to 10. The formula for computing the distance between two points is given by √(x2 − 1)² + (32 − Y₁ )² Test your program to test all cases. Two sample runs are shown here. Enter a point with two coordinates: 4 5 Enter Point (4, 5) is in the circle Enter a point with two coordinates: 99 Point (9, 9) is not in the circle Enter
Expert Solution
Step 1

#include <iostream>  
#include <cmath>
using namespace std;  
  
int main()  
{  
    int cx, cy, radius, x, y, distance;  
  
    cout<<"Enter the center point(cx, cy):\n";  
    cin>>cx>>cy;  
  
    cout<<"Enter radius of the circle:\n";  
    cin>>radius;  
  
    cout<<"Enter the point(x, y) to check its position\n";  
    cin>>x>>y;  
  
    distance = sqrt( pow( (x - cx), 2 ) + pow( (y - cy), 2 ) );  
  
    if(distance < radius)  
    {  
        cout<<"Point" <<x,y)<<"in side circle"; 
    }  
    else if(distance > radius)  
    {  
        cout<<"Point"<<(x,y)<<"is not in the circle";  
    }  
    else  
    {  
        cout<<"Point"<<(x,y)<<"is on the circle";  
    }  
  
    return 0;  
}  

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