My question is can I write this code in a different and easier way .? Python code:# there is only one rootdef fn(x):return x**3 - x - 2# define bisection methoddef bisection ( eq, segment, app = 0.3):a, b = segment ['a'1, segment ['b']Fa, Fb = eq(a), eq(b)if Fa * Fb > 0:raise Exception( 'No change of sign bisection not possible')while( b- a > app ):x = ( a + b) / 2.0f = eq(x)if f * Fa > 0: a = xelse: b = xreturn x#test itprint bisection ( fn, {'a':1, 'b':2}, 0.00003)

Note: There are changes made in few line , while rest of the code is same. Program approach:…

Python code: # there is only one root def fn(x): return x**3 - x - 2 # define bisection method def bisection( eq, segment, app = 0.3): a, b segment['a'l, segment['b'] Fa, Fb eq(a), eq(b) if Fa * Fb > 0: raise Exception( 'No change of sign bisection not possible')

Python code: # there is only one root def fn(x): return x**3 - x - 2 # define bisection method def bisection( eq, segment, app = 0.3): a, b segment['a'l, segment['b'] Fa, Fb eq(a), eq(b) if Fa * Fb > 0: raise Exception( 'No change of sign bisection not possible')

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

My question is can I write this code in a different and easier way .?

Python code:
# there is only one root
def fn(x):
return x**3 - x - 2
# define bisection method
def bisection ( eq, segment, app = 0.3):
a, b = segment ['a'1, segment ['b']
Fa, Fb = eq(a), eq(b)
if Fa * Fb > 0:
raise Exception( 'No change of sign bisection not possible')
while( b- a > app ):
x = ( a + b) / 2.0
f = eq(x)
if f * Fa > 0: a = x
else: b = x
return x
#test it
print bisection ( fn, {'a':1, 'b':2}, 0.00003)

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