(P(x)√(x)) = \x [~ (~P(x) VQ(x)] =x[~P(x) Q (~)] also [~~)~P(x)] So, using the above result and Ⓒ we get *₂ [~P(x) + (~P(~) AQ(~))] because PY Q ) PR then O - (: P(x) = ~ (~P(x)) ( ~ PV Q = P +Q) (: ~P~P) (:: PP) 2 P→ QAR
(P(x)√(x)) = \x [~ (~P(x) VQ(x)] =x[~P(x) Q (~)] also [~~)~P(x)] So, using the above result and Ⓒ we get *₂ [~P(x) + (~P(~) AQ(~))] because PY Q ) PR then O - (: P(x) = ~ (~P(x)) ( ~ PV Q = P +Q) (: ~P~P) (:: PP) 2 P→ QAR
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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100%
CAN YOU EXPLAIN THIS? I NEED A SCRIPT FOR THIS
![(P(x)\Q(x)) = \x [~ (~P(x)) VQ(x)]
=x[~(~) Q (20)]
also
\ [~P(x)~P(x)]
so, using the above result and ☺
we
get
*2 [~P(x) + (~P(x)^Q(x))]
because
P - Q
PR
then
(:: P(x) =~ (~P(x)))
(: ~PV Q = P +Q)
(: ~P~P)
( :: P→ P )
р э ала](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45631b76-92ed-4621-943e-a0001c817b2f%2Fc1f948df-4bcc-460c-9f45-39e90fd635fc%2Fazt8r6t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(P(x)\Q(x)) = \x [~ (~P(x)) VQ(x)]
=x[~(~) Q (20)]
also
\ [~P(x)~P(x)]
so, using the above result and ☺
we
get
*2 [~P(x) + (~P(x)^Q(x))]
because
P - Q
PR
then
(:: P(x) =~ (~P(x)))
(: ~PV Q = P +Q)
(: ~P~P)
( :: P→ P )
р э ала
![how
we
A
because
v (~P(X)^Q(x)) + R(x)
are also
from
va (~P(x)+) R(x))
рэа
from 3
vx [~R(x)~ (~P(x))]
Q→ ~P
also
because
given that
2
P - Q
3
QIR
= ~
vx [~R(~) - P(x)]
—
then
Hence proved.
4
3
PIR
(contrapositive)
(: ~ (~P(~)) = P(x))](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45631b76-92ed-4621-943e-a0001c817b2f%2Fc1f948df-4bcc-460c-9f45-39e90fd635fc%2F6876mw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:how
we
A
because
v (~P(X)^Q(x)) + R(x)
are also
from
va (~P(x)+) R(x))
рэа
from 3
vx [~R(x)~ (~P(x))]
Q→ ~P
also
because
given that
2
P - Q
3
QIR
= ~
vx [~R(~) - P(x)]
—
then
Hence proved.
4
3
PIR
(contrapositive)
(: ~ (~P(~)) = P(x))
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