One approximation to describe the real gas is:P(Vb)= RTe e RTVGivena(SP) = ( (V-V²T7 ² ) e-RT(V-b)²RTV = Pa(RTV²Solve for temperature (T.), pressure (Pc) at the criticalpoint.Hint: they are solved the same way as the Van deWaals gas case.V²)

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P(V-b) = RTe RTV Given RT a (OP) (3²) - (²-4² - (P²) - - P(x-4) = (₁ e RTV = (V-6) (V-b)² RTV² Solve for temperature (T.), pressure (P) at the critical point. Hint: they are solved the same way as the Van de Waals gas case.

P(V-b) = RTe RTV Given RT a (OP) (3²) - (²-4² - (P²) - - P(x-4) = (₁ e RTV = (V-6) (V-b)² RTV² Solve for temperature (T.), pressure (P) at the critical point. Hint: they are solved the same way as the Van de Waals gas case.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

One approximation to describe the real gas is:
P(Vb)= RTe e RTV
Given
a
(SP) = ( (V-V²
T7 ² ) e-
RT
(V-b)²
RTV = P
a
(RTV²
Solve for temperature (T.), pressure (Pc) at the critical
point.
Hint: they are solved the same way as the Van de
Waals gas case.
V²)

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