Putting it all together! Radioisotopes are often used in diagnostic imaging for detecting disease. The isotope 64Cu (copper-64), which has a half-life of 12.7 hours, is used to study diseases affecting copper metabolism such as Wilson's disease. What percentage of the original activity in the sample remains after 38.0 hours? Show your work, include units, and pay attention to significant figures. Hint: Remember that this process follows first order kinetics and 0.693 t1/2 that half-life is given by: k =

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### Transcription and Explanation for Educational Website

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**Topic: Application of Radioisotopes in Medical Diagnostics**

**11. Putting it all together!** Radioisotopes are often used in diagnostic imaging for detecting disease. The isotope \(^{64}\text{Cu}\) (copper-64), which has a half-life of 12.7 hours, is used to study diseases affecting copper metabolism such as Wilson’s disease. What percentage of the original activity in the sample remains after 38.0 hours? **Show your work, include units, and pay attention to significant figures.**

**Hint:** Remember that this process follows first-order kinetics and that half-life is given by: 

\[
k = \frac{0.693}{t_{1/2}}
\]

### Detailed Explanation

**Concepts:**

1. **Radioisotopes:** Radioisotopes are unstable isotopes of an element that decay and emit radiation. They are used in medical diagnostics for imaging and studying metabolic processes.

2. **Half-Life (\(t_{1/2}\))**: The time required for half of the radioactive nuclei in a sample to decay. For \(^{64}\text{Cu}\), this is 12.7 hours.

3. **First-Order Kinetics:** Radioactive decay processes are often first-order, meaning the rate is directly proportional to the number of undecayed nuclei present.

4. **Decay Constant (\(k\))**: This is a constant used to describe the rate of decay:

   \[
   k = \frac{0.693}{t_{1/2}}
   \]

**Problem Solving:**

To find out the remaining percentage of \(^{64}\text{Cu}\) after 38.0 hours:

1. **Calculate \(k\):**

   \(t_{1/2} = 12.7 \, \text{hours}\)

   \[
   k = \frac{0.693}{12.7 \, \text{hours}}
   \]

2. **Use the formula for first-order decay:**

   The fraction of the remaining activity (N) at time \(t\) relative to the initial activity \(N_0\) is given by:

   \[
   N = N_0 \times e^{-kt}
   \]

   Where \(t = 38.0 \, \text{hours}\).
Transcribed Image Text:### Transcription and Explanation for Educational Website --- **Topic: Application of Radioisotopes in Medical Diagnostics** **11. Putting it all together!** Radioisotopes are often used in diagnostic imaging for detecting disease. The isotope \(^{64}\text{Cu}\) (copper-64), which has a half-life of 12.7 hours, is used to study diseases affecting copper metabolism such as Wilson’s disease. What percentage of the original activity in the sample remains after 38.0 hours? **Show your work, include units, and pay attention to significant figures.** **Hint:** Remember that this process follows first-order kinetics and that half-life is given by: \[ k = \frac{0.693}{t_{1/2}} \] ### Detailed Explanation **Concepts:** 1. **Radioisotopes:** Radioisotopes are unstable isotopes of an element that decay and emit radiation. They are used in medical diagnostics for imaging and studying metabolic processes. 2. **Half-Life (\(t_{1/2}\))**: The time required for half of the radioactive nuclei in a sample to decay. For \(^{64}\text{Cu}\), this is 12.7 hours. 3. **First-Order Kinetics:** Radioactive decay processes are often first-order, meaning the rate is directly proportional to the number of undecayed nuclei present. 4. **Decay Constant (\(k\))**: This is a constant used to describe the rate of decay: \[ k = \frac{0.693}{t_{1/2}} \] **Problem Solving:** To find out the remaining percentage of \(^{64}\text{Cu}\) after 38.0 hours: 1. **Calculate \(k\):** \(t_{1/2} = 12.7 \, \text{hours}\) \[ k = \frac{0.693}{12.7 \, \text{hours}} \] 2. **Use the formula for first-order decay:** The fraction of the remaining activity (N) at time \(t\) relative to the initial activity \(N_0\) is given by: \[ N = N_0 \times e^{-kt} \] Where \(t = 38.0 \, \text{hours}\).
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