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Put the compounds in order of INCREASING oxidation state. он 0=c=0 HO, A B.

Put the compounds in order of INCREASING oxidation state. он 0=c=0 HO, A B.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Title: Understanding Oxidation States in Organic Compounds** **Task: Arrange the Compounds by Increasing Oxidation State** This exercise involves evaluating four different organic compounds and arranging them in order of increasing oxidation state. Each compound is represented by a structural formula, which can offer insights into their oxidation levels based on the functional groups present. **Compounds:** - **Compound A:** CO\(_2\): This compound is carbon dioxide, consisting of two oxygen atoms double-bonded to a central carbon atom. - **Compound B:** Cyclohexanol: This is a six-membered carbon ring (cyclohexane) with an alcohol (-OH) group attached to one carbon. - **Compound C:** Butanal: This is a four-carbon chain with an aldehyde group (-CHO) at the end. It consists of three single-bonded carbon atoms followed by a carbon atom double-bonded to an oxygen atom and single-bonded to a hydrogen atom. - **Compound D:** Acetic Acid: This is a two-carbon molecule with a carboxyl (-COOH) group. The structure includes a carbon atom double-bonded to an oxygen atom and single-bonded to both another oxygen and a methyl group (CH\(_3\)). **Objective:** Determine which compound has the lowest oxidation state and which has the highest. Oxidation states in organic chemistry often relate to the number and types of bonds (especially to oxygen or other electronegative atoms) a carbon atom forms. **Consideration:** - Alcohol groups vs. carboxyl and carbonyl groups. - More bonds to oxygen usually indicate a higher oxidation state. - Carbon dioxide represents a fully oxidized form of carbon. **Conclusion:** Arrange the compounds starting from the one with the lowest oxidation state to the highest. This kind of exercise is crucial for understanding redox reactions in organic chemistry, especially in biochemical contexts such as metabolism.
Transcribed Image Text:**Title: Understanding Oxidation States in Organic Compounds** **Task: Arrange the Compounds by Increasing Oxidation State** This exercise involves evaluating four different organic compounds and arranging them in order of increasing oxidation state. Each compound is represented by a structural formula, which can offer insights into their oxidation levels based on the functional groups present. **Compounds:** - **Compound A:** CO\(_2\): This compound is carbon dioxide, consisting of two oxygen atoms double-bonded to a central carbon atom. - **Compound B:** Cyclohexanol: This is a six-membered carbon ring (cyclohexane) with an alcohol (-OH) group attached to one carbon. - **Compound C:** Butanal: This is a four-carbon chain with an aldehyde group (-CHO) at the end. It consists of three single-bonded carbon atoms followed by a carbon atom double-bonded to an oxygen atom and single-bonded to a hydrogen atom. - **Compound D:** Acetic Acid: This is a two-carbon molecule with a carboxyl (-COOH) group. The structure includes a carbon atom double-bonded to an oxygen atom and single-bonded to both another oxygen and a methyl group (CH\(_3\)). **Objective:** Determine which compound has the lowest oxidation state and which has the highest. Oxidation states in organic chemistry often relate to the number and types of bonds (especially to oxygen or other electronegative atoms) a carbon atom forms. **Consideration:** - Alcohol groups vs. carboxyl and carbonyl groups. - More bonds to oxygen usually indicate a higher oxidation state. - Carbon dioxide represents a fully oxidized form of carbon. **Conclusion:** Arrange the compounds starting from the one with the lowest oxidation state to the highest. This kind of exercise is crucial for understanding redox reactions in organic chemistry, especially in biochemical contexts such as metabolism.
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